简体   繁体   English

去例行死锁?

[英]go routine dead lock?

I am new to golang , and I am puzzled with this deadlock ( run here ) 我是golang ,对此僵局感到困惑( 在此处运行

package main

import (
    "fmt"
    "runtime"
    "time"
)

func main() {
    c := make(chan string)
    work := make(chan int, 1)
    clvl := runtime.NumCPU()
    count := 0
    for i := 0; i < clvl; i++ {
        go func(i int) {
            for jdId := range work {
                time.Sleep(time.Second * 1)
                c <- fmt.Sprintf("done %d", jdId)
            }
        }(i)
    }

    go func() {
        for i := 0; i < 10; i++ {
            work <- i
        }

        close(work)
    }()

    for resp := range c {
        fmt.Println(resp, count)
        count += 1
    }
}

You never close c , so your for range loop waits forever. 您永远不会关闭c ,因此for range循环会永远等待。 Close it like this: 像这样关闭它:

var wg sync.WaitGroup
for i := 0; i < clvl; i++ {
    wg.Add(1)
    go func(i int) {
        defer wg.Done()
        for jdId := range work {
            time.Sleep(time.Second * 1)
            c <- fmt.Sprintf("done %d", jdId)
        }
    }(i)
}

go func() {
    for i := 0; i < 10; i++ {
        work <- i
    }

    close(work)
    wg.Wait()
    close(c)
}()

EDIT : Fixed the panic, thanks Crast 编辑 :修复了恐慌,谢谢克雷斯特

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM