发送文件作为来自ajax请求的响应

Question

I have a javascript function that sends the name of the audio file on my server to a php script using jquery get. It looks like this:

function getAudioClip() {
    var x = document.getElementById("clips").value;
    $.get( "get_audio.php", { filename: x } )
      .done(function( data ) {
        loadAudioClip(data);
      });
}

The function loadAudioClip(data) displays the waveform of the audio file given as data. I want to make get_audio.php return the audio file with the file name x, so I can use it to display the waveform using my loadAudioClip(data) function.

Edit: I figured out that maybe I can get a file directly instead of using php, like this

function getAudioClip() {
    var x = document.getElementById("clips").value;
    $.get( "audio/" + x , function( data ) {
      loadAudioClip(data);
    });
}

Is that possible? x is a filename(ex. MyRecording02.wav).

Answer 1

Opening an audio file with PHP will be slow process. Maybe you can check the existence of the file with PHP, and then if file exists, simply do something like this:

header("Location: $filename");