[英]cannot receive datagram correctly in python3 asyncio
I write simple udp client program, but it cannot receive datagram correctly. 我编写了简单的udp客户端程序,但无法正确接收数据报。
My code is below. 我的代码如下。
import asyncio
class EchoClientProtocol:
def __init__(self, message, loop):
self.message = message
self.loop = loop
self.transport = None
def connection_made(self, transport):
self.transport = transport
print('Send:', self.message)
self.transport.sendto(self.message.encode())
def datagram_received(self, data, addr):
print('Received:', data.decode())
async def sendChar(transport, msg):
print('send: ', msg)
transport.sendto(msg.encode())
if __name__ == '__main__':
loop = asyncio.get_event_loop()
message = 'Hello World!'
connect = loop.create_datagram_endpoint(
lambda: EchoClientProtocol(message, loop),
remote_addr=('127.0.0.1', 9999)
)
transport, protocol = loop.run_until_complete(connect)
while (True):
try:
ch = input()
except KeyboardInterrupt:
break
loop.run_until_complete(sendChar(transport, ch))
loop.run_forever()
transport.close()
loop.close()
And I write UDP echo server protocol program posted in asyncio document. 并且我写了asyncio文件中发布的UDP echo server协议程序。
( https://docs.python.org/3/library/asyncio-protocol.html#udp-echo-server-protocol ) ( https://docs.python.org/3/library/asyncio-protocol.html#udp-echo-server-protocol )
Running these programs, I think result is like this. 运行这些程序,我认为结果是这样的。
Send: Hello World!
Received: Hello World!
1
send: 1
Received: 1
2
send: 2
Received: 2
But result is this. 但是结果是这个。
Send: Hello World!
1
send: 1
Received: Hello World!
2
send: 2
Received: 1
Why is result shifted? 为什么结果会转移?
I search about asyncio module, but I cannot solve this problem. 我搜索有关asyncio模块的信息,但无法解决此问题。
It is because while True
loop does not give back control to ioloop until next send call - input
is blocking. 这是因为while True
循环在下一次发送调用之前不会将控制权交还给ioloop- input
处于阻塞状态。 Simply add some async sleep, so ioloop could handle events to receive data 只需添加一些异步睡眠,以便ioloop可以处理事件以接收数据
while (True):
try:
loop.run_until_complete(asyncio.sleep(0.001))
ch = input()
except KeyboardInterrupt:
break
loop.run_until_complete(sendChar(transport, ch))
And since input
will block here as well, afaik it is the best to move it to separate thread: 由于input
也会在此处阻塞,因此afaik最好将其移至单独的线程:
import threading
import asyncio
class EchoClientProtocol:
def __init__(self, message, loop):
self.message = message
self.loop = loop
self.transport = None
def connection_made(self, transport):
self.transport = transport
print('Send:', self.message)
self.transport.sendto(self.message.encode())
def datagram_received(self, data, addr):
print('Received:', data.decode())
def error_received(self, data, addr=None):
raise data
async def sendChar(transport, msg):
print('send: ', msg)
transport.sendto(msg.encode())
user_input = [None]
# spawn a new thread to wait for input
def get_user_input(user_input_ref):
while True:
user_input_ref[0] = input()
if __name__ == '__main__':
loop = asyncio.get_event_loop()
message = 'Hello World!'
connect = loop.create_datagram_endpoint(
lambda: EchoClientProtocol(message, loop),
remote_addr=('127.0.0.1', 9999)
)
transport, protocol = loop.run_until_complete(connect)
input_thread = threading.Thread(target=get_user_input, args=(user_input,))
input_thread.daemon = True
input_thread.start()
while (True):
if user_input[0] is not None:
loop.run_until_complete(sendChar(transport, user_input[0]))
user_input[0] = None
loop.run_until_complete(asyncio.sleep(1))
loop.run_forever()
transport.close()
loop.close()
I have mixed your code with waiting for user input in separate thread , of course to refactor :) 我将您的代码与等待用户输入的单独线程混合在一起,以便进行重构:)
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