将char插入字符串以结束数字

Question

I have ugly string:

oldstr = "0.100% fDrg: 2%,dgdv: 29% fGd dg 0.2%, Ghh-sf 2.2 dbgh: NONE dfgdf6 gd 3 "

I need to insert char | after the last digit of number for next splitting by this inserted | . There is also value none , where is also added this separator:

0.100| fdrg: 2|,dgdv: 29| fgd dg 0.2|, ghh-sf 2.2|dbgh: none| dfgdf6|gd 3|

I try this, but no success:

print re.sub(r'(\d+[a-z %^.])', r'\1|', oldstr.lower())

0.|100%| fdrg: 2%|,dgdv: 29%| fgd dg 0.|2%|, ghh-sf 2.|2 |dbgh: none dfgdf6 |gd 3 |

Any help will be appreciated.

Answer 1

How about:

>>> re.sub(r"([\d\.]+|NONE)%?", r"\1|", oldstr)
'0.100| fDrg: 2|,dgdv: 29| fGd dg 0.2|, Ghh-sf 2.2| dbgh: NONE| dfgdf6| gd 3| '

Here we are capturing one or more occurences of digits and dots or a NONE in a capturing group (followed by an optional % sign) and replacing it with itself and a pipe character.

Note that @Wiktor's capturing part of the regular expression is much better than in this answer.

Answer 2

You can use

(\bnone\b|\d+(?:\.\d+)?)%?

And replace with \\1| .

Explanation :

• (\\bnone\\b|\\d+(?:\\.\\d+)?) - Group 1 matching 2 alternatives:
  • \\bnone\\b - whole word none
  • | - or...
  • \\d+(?:\\.\\d+)? - a float value ( \\d+ matches one or more digits, and (?:\\.\\d+)? matches (optionally) a dot followed with one or more digits)
• %? - an optional (since ? means match one or zero times ) % symbol

See regex demo

Python code:

import re
p = re.compile(ur'(\bnone\b|\d+(?:\.\d+)?)%?', re.IGNORECASE)
test_str = "0.100% fDrg: 2%,dgdv: 29% fGd dg 0.2%, Ghh-sf 2.2 dbgh: NONE dfgdf6 gd 3 "
subst = "\1|"
result = re.sub(p, subst, test_str)

If you need to trim the values, you will be able to do it after splitting. Also, none can be turned lower case before processing the text with re.sub(r'\\b\\none\\b', 'NONE', input) .

Answer 3

import re
oldstr = "0.100% fDrg: 2%,dgdv: 29% fGd dg 0.2%, Ghh-sf 2.2 dbgh: NONE dfgdf6 gd 3"

newstring = re.sub(r"([\.\d]+)", r"\1|", oldstr)
print newstring.replace("%","").replace("NONE","NONE|")

output:

0.100| fDrg: 2|,dgdv: 29| fGd dg 0.2|, Ghh-sf 2.2| dbgh: NONE| dfgdf6| gd 3|

After a little more thinking here is a one-liner:

print re.sub(r"([\.\d'NONE']+)%?", r"\1|", oldstr)