觉得我的Ajax有问题吗？
[英]Think something's wrong with my ajax?
问题描述
What I want to do is return the echo value of "addTemplate.php" when I send it a form value via a http POST request. 
我想做的是当我通过http POST请求发送表单值时返回“ addTemplate.php”的回显值。 However, when I send the request, absolutely nothing happens. 但是，当我发送请求时，绝对没有任何反应。
What should I do? 我该怎么办？
Here's my JS 这是我的JS
$(document).ready(function() {
$("#sendTemplate").on("submit", function(event) {
var template = $("#template").val();
event.preventDefault();
$.ajax({method: "POST", url: "addTemplate.php", data: template, success: function(result) {
alert(result);
});
});
});
Here's my html 这是我的HTML
<!DOCTYPE html>
<html>
<head>
<title>Admin</title>
<link type="text/css" rel="stylesheet" href="stylesheet.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script src="adminscript.js"></script>
</head>
<body>
<h1>Admin/Developer page</h1>
<form id="sendTemplate">
<p>Enter a new template for the server: (Enter #word to enter a placeholder for words)</p><input type="text" name="template" id="template">
<input type="submit" name="submit">
</form>
<div id='success'></div>
<br><br><br><br>
<form action="turing.html">
<button type="submit">Home</button>
</form>
</body>
</html>
And here is my php 这是我的PHP
$template = $_POST["template"];
if(strlen($template) <= 100 && strpos($template, "#word")) {
file_put_contents("templates.txt", "\r\n" . $template, FILE_APPEND);
header("Location: http://community.dur.ac.uk/h.j.g.baum/admin.html");
echo "True";
}
else {
echo "False";
}
What's wrong with my code (most likely in the JavaScript) and how can I improve it? 我的代码出了什么问题（很可能是在JavaScript中），我该如何加以改进？
Thanks 谢谢
4 个解决方案
解决方案1
1 2016-01-18 19:36:46
Replace ajax data: 替换ajax数据：
data: template,
With: 带有：
data: "template="+template,
Issue: 问题：
You are using $_POST['template'] for getting values and didn't define in ajax data. 您正在使用$ _POST ['template']获取值，但未在ajax数据中定义。
解决方案2
0 2016-01-18 19:34:12
I think you're missing a closing curly on the Ajax success function 我认为您缺少Ajax成功功能的结束功能
$(document).ready(function() {
$("#sendTemplate").on("submit", function(event) {
var template = $("#template").val();
event.preventDefault();
$.ajax({method: "POST", url: "addTemplate.php", data: template, success: function(result) {
alert(result);
}});
});
});
解决方案3
0 2016-01-18 19:34:44
id do this: id这样做：
$(document).ready(function () {
$("#sendTemplate").on("submit", function () {
$.ajax({
method: "POST",
url: "addTemplate.php",
data: $(this).serialize(),
success: function (result) {
alert(result);
});
return false;
});
});
解决方案4
0 2016-01-18 19:39:26
Just change your js to 只需将您的js更改为
$(document).ready(function() {
$("#sendTemplate").on("submit", function(event) {
var template = $("#sendTemplate").serialize();
$.ajax({method: "POST", url: "test.php", data: template, success: function(result) {
alert(result);
}});
event.preventDefault();
});
And 和
<form id="sendTemplate">
to 至
<form id="sendTemplate" method="POST">
This is the right way to get the form data and pass it to your php script 这是获取表单数据并将其传递给您的php脚本的正确方法
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