[英]Printing specific lines of log file - Python
I want to print specific content of the file from the log.. for each line in the file - printing the whole line. 我想从日志中打印文件的特定内容..对于文件中的每一行 - 打印整行。 instead of th
而不是
with open(sys.argv[1], 'r') as f:
for line in f:
if "Trace log :" in line:
print line
This works fine. 这很好用。
If I want to be more specific about the line : if "Trace log : {"request":{"http"":
then print the trace log content; 如果我想更具体一点:
if "Trace log : {"request":{"http"":
然后打印跟踪日志内容; getting an error. 得到一个错误。
if "Trace log : {"request":{"http"":
^
SyntaxError: invalid syntax SyntaxError:语法无效
any help would be greatly appreciated. 任何帮助将不胜感激。
@Maroun answered this is in a comment, I am writing an answer for future reference: @Maroun回答这是在评论中,我正在写一个答案以供将来参考:
A string may not contain the quotation used to start it: 字符串可能不包含用于启动它的引用:
>>> 'foo' # OK
'foo'
>>> 'fo'' # Starts with ' and has ' inside, NOT OK
SyntaxError: EOL while scanning string literal
Either use another starting quote or escape the inside quote: 要么使用另一个起始引用,要么逃避内部引用:
>>> "fo'o"
"fo'o"
>>> 'fo\'o'
"fo'o"
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