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为变量分配可选的返回值

[英]Assign optional return value to variable

I have a method which can return nil. 我有一个可以返回nil的方法。 If it doesn't return nil, it should replace a local variable: 如果未返回nil,则应替换局部变量:

NSString *errorMsg = error.localizedDescription;
if([self errorMsgFromErrorCode:error.code]) {
    errorMsg = [self errorMsgFomErrorCode:error.code];
}

Is there a smarter more compact way to do this without having to call this helper method twice? 是否有一种更智能,更紧凑的方式来执行此操作,而无需两次调用此辅助方法?

errorMsg = [self errorMsgFromErrorCode:error.code] ?: error.localizedDescription;

you can use conditional operator: 您可以使用条件运算符:

NSString *errormessage = [self errorMsgFromErrorCode:error.code] ? [self errorMsgFromErrorCode:error.code] : error.localizedDescription;

and in swift the shortest form is nil coalescing operator (??) for eg 且最短形式为nil合并运算符(??),例如

var perhapsInt: Int?
let definiteInt = perhapsInt ?? 2
print(definiteInt) // prints 2 
perhapsInt = 3
let anotherInt = perhapsInt ?? 4
print(anotherInt) // prints 3

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