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隐式html日期值转换为RFC 2822

[英]Covert html date value to RFC 2822

I have following code, 我有以下代码,

$date = $_POST["s-date"]; // get from  form. value pass correctly. 
 $time =  "".$hour.":".$minute.":".$second.""; // ok
   echo RFC2822($date,$time);   

function RFC2822($date,$time = '00:00') { 
   $array =  list($d, $m, $y) = explode('-', $date); 
    list($h, $i, $s) = explode(':', $time);

    return date('r', mktime($h,$i,0,$m,$d,$y));
}

When I execute this script, time fragment is printed correctly, But date is displayed as Jul 08 2025 always even passing different date to the function. 当我执行此脚本时,将正确打印时间片段,但日期始终显示为2025年7月8日,甚至将不同的日期传递给函数。 How to fix this. 如何解决这个问题。

You must need to check the value of this input $_POST["s-date"] it must be follow this format of date: 您必须检查此输入$_POST["s-date"]它必须遵循以下日期格式:

`DD-MM-YY`

because, you are creating list in this format (DD-MM-YY): 因为,您正在以以下格式(DD-MM-YY)创建列表:

$array =  list($d, $m, $y) = explode('-', $date);

UPDATE 1: 更新1:

As you mentioned, you are using HTML date and HTML date format is 'YYYY-MM-DD' , now just change the list variable order as per date format. 如前所述,您使用的是HTML日期,而HTML日期格式为'YYYY-MM-DD' ,现在只需更改日期格式的列表变量顺序即可。

From what I can gather your problem lies not with the code you've shared, but somewhere else. 据我所知,您的问题不在于您共享的代码,而在于其他地方。 If I copy-paste your script and put in a fixed date on $date, it works as expected. 如果我复制粘贴您的脚本并在$ date上放置一个固定的日期,它将按预期工作。 (I've removed $time for missing vars) (我已删除缺少变量的$ time)

$date = "27-02-2014";
echo RFC2822($date);   

function RFC2822($date,$time = '00:00:00') {
   $array =  list($d, $m, $y) = explode('-', $date);
    list($h, $i, $s) = explode(':', $time);

    return date('r', mktime($h,$i,0,$m,$d,$y));
}

Outputs 产出

Thu, 27 Feb 2014 12:00:00 +0100

From this I expect that your $_POST['s-date'] var somehow gets a fixed 08-07-2025 or some other input that will make it 08 Jul 2025. 由此,我希望您的$_POST['s-date'] var以某种方式获得固定的08-07-2025或其他一些输入,使其变为2025年7月8日。

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