[英]gulp watch is not always working
Sometimes gulp watch is not working when I save a javascript file. 有时,当我保存JavaScript文件时,gulp watch无法正常工作。 This is my watch task below.
这是我下面的观看任务。
gulp.task('watch', function() {
gulp.watch('./src/**/*.js', ['js']);
});
I do have a bunch of sub directories. 我确实有一堆子目录。 Would it be advisable to make my watch task be more specific like:
建议使我的监视任务更具体,例如:
gulp.task('watch', function() {
gulp.watch('./src/*.js', ['js']);
gulp.watch('./src/dir1/**/*.js', ['js']);
gulp.watch('./src/dir2/**/*.js', ['js']);
});
You need to make your task slightly more specific. 您需要使您的任务更加具体。
With './src/**/*.js' you are only watching javascript files in sub folders, not in the first level of ./src/ 使用“ ./src/**/*.js”,您仅查看子文件夹中的javascript文件,而不是./src/的第一级
Having gulp.watch(['./src/**/*.js', './src/*.js'], ['js'])
will work. 使用
gulp.watch(['./src/**/*.js', './src/*.js'], ['js'])
使用。 Keep in mind watch can take an array of strings to watch for, don't call it multiple times. 请注意,watch可以使用字符串数组进行监视,请勿多次调用。
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