正则表达式字符之间的第一个字符串
[英]Regex first string between characters
问题描述
I have this string 
我有这串
_text = 'ITEM|6945541514535242|2|'
and how can I retrieve this string '6945541514535242' with regex? 以及如何使用正则表达式检索此字符串'6945541514535242' ？
'6945541514535242' and '2' are between '|' '6945541514535242'和'2'在'|'之间 , but I want only get the first one. ，但我只想要第一个。
2 个解决方案
解决方案1
2 已采纳 2016-01-22 16:33:30
You can use regex \\|(\\d+)\\| 您可以使用正则表达式\\|(\\d+)\\| and re.search to get only the first match, if any. 和re.search如果有只得到了第一场比赛。
>>> _text = 'ITEM|6945541514535242|2|'
>>> re.search(r'\|(\d+)\|', _text).group(1)
'6945541514535242'
解决方案2
0 2016-01-22 17:11:37
If it can be any text you will need to do an 'non-greedy' search: 如果可以是任何文本，则需要进行“非贪婪”搜索：
>>> _text = 'ITEM|abcd6945541514535242|2|'
>>> re.search(r'\|(.*?)\|', _text).group(1)
'abdc6945541514535242'
the ? ？ makes it non-greedy so it matches as little as possible 使它变得非贪婪，因此尽可能少地匹配
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