注意：尝试在第5行的C：\\ xampp \\ htdocs \\ ihelploginapi \\ index.php中获取非对象的属性

Question

This code was working 2 days before, but now i am getting an error:

Trying to get property of non-object in C:\\xampp\\htdocs\\ihelploginapi\\index.php on line 4.

Somebody please help me out.

<?php

    $json = file_get_contents('php://input');
    $obj = json_decode($json,TRUE);
    $tag = $obj->{'tag'};
?>

Answer 1

json_decode does not give you an object. It gives you an array. You want to access it as such:

$tag = $obj['tag'];

or to re-write the var names more accurately

$json = file_get_contents('php://input');
$php_array = json_decode($json,TRUE);
$tag = $php_array['tag'];

Answer 2

在相关行中使用：

$tag = $obj['tag'];

Answer 3

The second argument to json_decode() tells it to convert JSON objects to PHP associative arrays, not PHP objects. So you need to use $obj['tag'] instead of $obj->tag . Or change the decode line to

$obj = json_decode($json);