将所有json解码对象转换为php中的数组

Question

I have a JSON decoded object(see the picture):

I want to convert whole object to array(also children object). When I do something like this

$parent_object = (array)$parent_object;

It converts only parent object, children objects are still objects. Is there way to convert all objects to array at once, instead of using (array) every time?

Answer 1

Does the solution from here help?

function object_to_array($obj) {
    if(is_object($obj)) $obj = (array) $obj;
    if(is_array($obj)) {
        $new = array();
        foreach($obj as $key => $val) {
            $new[$key] = object_to_array($val);
        }
    }
    else $new = $obj;
    return $new;       
}

This function recursively creates a new array which contains anything except objects

Answer 2

For a complex object, I was getting null chars within the array keys stemming from the simplification of the object when type-casted as (array).

When var_dumped , a(str) array key would look like this:

arrayKey (str 9 chars, with the null char hidden within) the actual string: array(NULL CHAR)Key

The best way to deal with it is to further clean the keys by removing null chars (char 0).

This adaptation works:

function objectToArray($obj) {
    if(is_object($obj)) {
        $obj = (array) $obj;
        $aobj = array();
        foreach ($obj as $key=>$value) {
            $aobj[_cleanStr($key)] = $value; //sanitize the str for null chars
        }
        $obj = $aobj;
    }
    if(is_array($obj)) {
        $new = array();
        foreach($obj as $key => $val) {
            $new[_cleanStr($key)] = objectToArray($val);
        }
    }
    else $new = $obj;

    return $new;
}

//Clean string
function _cleanStr($str) {
    $str = str_replace("", "", $str); //remove null chars
    return $str;
}

Answer 3

最好为json_decode（）函数设置第二个参数TRUE （ 当为TRUE ，返回的objects将被转换为关联arrays 。 ）像这样 -

json_decode($json, TRUE);