preg_match_all和preg_replace foreach循环

Question

I'm trying to convert [quote="author"]text[/quote] to a formatted div block.

$p_text :

[quote="person1"]Hello![/quote]
[quote="person2"]Hi![/quote]

Function:

function bbCode($p_text){

      $pattern = '/\[quote="(.+?)"\]/'; // matches the author name, i.e. person1
      preg_match_all($pattern, $p_text, $matches);

      $authorCounter = 0;

      foreach ($matches as $matchgroup) {

        $author = $matchgroup[$authorCounter];

        $pattern1 = '/\[quote=".+?"\]/'; // captures [quote="..."]
        $replacement1 = '<div class="quote"><strong class="quote-author">' . $author . ' wrote:</strong><br>';
        $p_text = preg_replace($pattern1, $replacement1, $p_text);

        $authorCounter++;
      }

      $pattern2 = '/\[\/quote\]/'; // captures [/quote]
      $replacement2 = '</div>';
      $p_text = preg_replace($pattern2, $replacement2, $p_text);

      return $p_text;

}

This is replacing both quote's authors with "person2" because the second foreach iteration replaces the text again(?). How could I make sure each quote has the correct person's name?

Answer 1

You can do it with just one regex. The trick is to put certain parts of the search pattern in parenthesis and refer to those parts in the replace pattern using $1 , $2 and so on.

$string = '[quote="person1"]Hello![/quote][quote="person2"]Hi![/quote]';
$output = preg_replace('/\[quote="([^"]+)"\]([^[]+)\[\/quote\]/', '<div class="quote"><strong class="quote-author">$1 wrote:</strong><br>$2</div>', $string);

echo $output;

Output:

<div class="quote"><strong class="quote-author">person1 wrote:</strong><br>Hello!</div>
<div class="quote"><strong class="quote-author">person2 wrote:</strong><br>Hi!</div>

Live example at http://sandbox.onlinephpfunctions.com/code/3e8dd7798b29df5bd161eb01f7c11329fc13283f