[英]Retrieving a value and displaying it in a select option box in php
I am trying to retrieve a stored value from database and show it in a select option box. 我试图从数据库中检索存储的值,并将其显示在选择选项框中。 My problem is it's showing the first value as selected.
我的问题是它显示所选的第一个值。 my code is
我的代码是
$query = "SELECT * FROM bookwizard.book_inventory where bi_SKU='$SKU'";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$bid=($row{'bi_bookcondition_id'});
}
<select class='form-control' id='condition' name='condition'>
<option value='' <?php if (!empty($bid) && $bid == '' ) echo 'selected = 'selected'; ?> </option>
<option value='1' <?php if (!empty($bid) && $bid == '1') echo 'selected = 'selected'; ?>Good</option>
<option value='2' <?php if (!empty($bid) && $bid == '2') echo 'selected = 'selected'; ?>Old</option>
<option value='3' <?php if (!empty($bid) && $bid == '3') echo 'selected = 'selected'; ?>Bad</option>
</select>
Thanks for helping. 感谢您的帮助。
You have missed to close the options. 您错过了关闭选项的机会。 As well as
if
conditions are having error. 以及
if
条件具有错误。
Replace your selectbox code as below : 替换您的选择框代码,如下所示:
<select class='form-control' id='condition' name='condition'>
<option value='' <?php if (!empty($bid) && $bid == '' ) echo "selected = 'selected'"; ?>></option>
<option value='1' <?php if (!empty($bid) && $bid == '1') echo "selected = 'selected'"; ?>>Good</option>
<option value='2' <?php if (!empty($bid) && $bid == '2') echo "selected = 'selected'"; ?>>Old</option>
<option value='3' <?php if (!empty($bid) && $bid == '3') echo "selected = 'selected'"; ?>>Bad</option>
</select>
<?php
$query = "SELECT * FROM bookwizard.book_inventory where bi_SKU='$SKU'";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$bid=($row{'bi_bookcondition_id'});
?>
<select class='form-control' id='condition' name='condition'>
<option value='' <?php if(!empty($bid) && $bid == '' ){echo 'selected=selected';}?> ></option>
<option value='1' <?php if (!empty($bid) && $bid == '1'){echo 'selected=selected';} ?>>Good</option>
<option value='2' <?php if (!empty($bid) && $bid == '2'){ echo 'selected=selected';} ?>>Old</option>
<option value='3' <?php if (!empty($bid) && $bid == '3'){ echo 'selected=selected';} ?>>Bad</option>
</select>
<?php }?>
use this select option. 使用此选择选项。
Replace your code with this :
<?php
$query = "SELECT * FROM bookwizard.book_inventory where bi_SKU='$SKU'";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$bid=($row{'bi_bookcondition_id'});
?>
<select class='form-control' id='condition' name='condition'>
<option value='' <?php if(!empty($bid) && $bid == '' ){echo 'selected=selected';}?> ></option>
<option value='1' <?php if (!empty($bid) && $bid == '1'){echo 'selected=selected';} ?>>Good</option>
<option value='2' <?php if (!empty($bid) && $bid == '2'){ echo 'selected=selected';} ?>>Old</option>
<option value='3' <?php if (!empty($bid) && $bid == '3'){ echo 'selected=selected';} ?>>Bad</option>
</select>
<?php }?>
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