[英]Get incomplete word matched with regular expression
I have a text and I need to find words which begens with one word, and I need to get the complete word which match with this expression. 我有一个文本,我需要找到一个单词衍生的单词,并且需要获取与此表达式匹配的完整单词。
Example: I search "abc"
in a text like: "Hi abc is abc123"
and I need to get an array with: [0] = "abc" and [1] = "abc123"
because both match with my expresion "abc"
. 示例:我在诸如
"Hi abc is abc123"
的文本中搜索"abc"
,并且我需要获取一个数组: [0] = "abc" and [1] = "abc123"
因为两者都与我的表达式"abc"
匹配"abc"
。
I have this code: 我有以下代码:
$words = [];
foreach($items as $i){
$text = $l->getText();
preg_match('*'."#".$q.'*', $text, $words[]);
}
But I get always [0] = "abc" and [1] = "abc"
. 但是我总是得到
[0] = "abc" and [1] = "abc"
。
How can I do this? 我怎样才能做到这一点?
//Regular expresson to find: 'abc', followed by any
//characters, until a whitespace character
$re = "/(abc[^\\s]*)/";
//String to search
$str = "Hi abc is abc123";
//Find all matches (/g)
preg_match_all($re, $str, $matches);
//Show matches in array
print_r($matches[0]);
Will output: 将输出:
Array ( [0] => abc [1] => abc123 )
数组([0] => abc [1] => abc123)
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