Jquery，PHP将Json数据发布到外部URL

Question

I have the following jquery function which is supposed to post data to a php function which in the process it passes it to the external script for processing. Below is my jquery function :

  function order_confirmation(json) {
                    $.ajax({
                        type: 'POST',
                        url: "<?php echo base_url(); ?>home/confirm_order_received/",
                        data: json,
                        contentType: 'application/json',
                        dataType: 'json',
                        success: function (data) {
                            console.log(data);
                        },
                        failure: function (errMsg) {
                            console.log(errMsg);
                        }
                    });
                }

This function is supposed to pass the json data to my php function which is below here :

  function confirm_order_received() {
        $json = $this->input->post('json');
        // Initialize curl
        $curl = curl_init();
        $externalscriptaddress = "http://197.237.132.178/api/order/order_upsert";
        // Configure curl options
        $opts = array(
            CURLOPT_URL => $externalscriptaddress,
            CURLOPT_RETURNTRANSFER => true,
            CURLOPT_CUSTOMREQUEST => 'POST',
            CURLOPT_POST => 1,
            CURLOPT_POSTFIELDS => $json
        );

        // Set curl options
        curl_setopt_array($curl, $opts);

        // Get the results
        $result = curl_exec($curl);

        // Close resource
        curl_close($curl);

        echo $result;
    }

I have a problem of how I am supposed to access the data from the php side, I have tried accessing it through the post : $json = $this->input->post('json'); and passed it to the CURLOPT_POSTFIELDS => $json but I get an error since nothing has been passed. Please advise how can i pass the json data to an external script?

Answer 1

要获取原始的帖子数据（在您的情况下），请使用file_get_contents("php://input")

Answer 2

Instead of data: json, you should use data: "json:json",

Using just data: json, will post the data, but it will not be assigned to a key. To access the data ou need to assign it to a key. By using data: "json:json", , you can access it with $json = $this->input->post('json');