[英]How do I populate a JSON array with values (not pairs) in Delphi?
I'm trying to create JSON that looks like this: 我正在尝试创建如下所示的JSON:
{ "guestlist": ["alice","bob","charlie"] }
Typical examples I see for populating a JSON array look like this: 我看到用于填充JSON数组的典型示例如下所示:
var
jsobj: TJsonObject;
jso : TJsonObject;
jsa : TJsonArray;
jsp : TJsonPair;
begin
jsObj := TJsonObject.Create();
jsa := TJsonArray.Create();
jsp := TJSONPair.Create('guestlist', jsa);
jsObj.AddPair(jsp);
jso := TJsonObject.Create();
jso.AddPair(TJSONPair.Create('person', 'alice'));
jsa.AddElement(jso);
jso := TJsonObject.Create();
jso.AddPair(TJSONPair.Create('person', 'bob'));
jsa.AddElement(jso);
jso := TJsonObject.Create();
jso.AddPair(TJSONPair.Create('person', 'charlie'));
jsa.AddElement(jso);
end;
But that would result in something like this: 但这会导致类似这样的事情:
{ "guestlist": [{"person":"alice"},{"person":"bob"},{"person":"charlie"}] }
How can I add a single value to the array instead of a pair? 如何将单个值添加到数组而不是一对? I see nothing in the documentation for TJsonObject
on how to do this, 我在TJsonObject
的文档中没有看到如何做到这一点,
This is actually a lot simpler than you're making it out to be. 这实际上比你想要的要简单得多。 A TJSONArray
can happily contain any TJSONValue
as elements so the solution is really quite straightforward. TJSONArray
可以愉快地包含任何TJSONValue
作为元素,因此解决方案非常简单。
program Project1;
{$APPTYPE CONSOLE}
uses
JSON;
var
LJObj : TJSONObject;
LGuestList : TJSONArray;
begin
LGuestlist := TJSONArray.Create();
LGuestList.Add('alice');
LGuestList.Add('bob');
LGuestList.Add('charlie');
LJObj := TJSONObject.Create;
LJObj.AddPair(TJSONPair.Create('guestlist', LGuestList));
WriteLn(LJObj.ToString);
ReadLn;
end.
Produces output : 产生输出:
{"guestlist":["alice","bob","charlie"]}
Just in case you'd be interested in looking at an alternative: I created jsonDoc , primarily because I like COM interfaces and OleVariants, and dislike long lists of overloads. 如果你有兴趣看一个替代方案:我创建了jsonDoc ,主要是因为我喜欢COM接口和OleVariants,并且不喜欢长的重载列表。 Then the above code could like like this: 那么上面的代码可能是这样的:
JSON(['guestlist',
VarArrayOf([JSON(['person','alice']),
JSON(['person','bob']),
JSON(['person','charlie'])
])
])
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.