在变量中获取sql查询的结果

Question

I have a simple MySQL Database setup.

When I execute in MySQL shell:

"SELECT count(serverid) as num FROM servers WHERE owner_id = 1"

it says:

+-----+
| num |
+-----+
|   4 |
+-----+

which is correct. In php i want one variable having the value 4 .

$pdo = new PDO('mysql:host=localhost;dbname=cswebin', 'root', 'password');
 $statement = $pdo->prepare("SELECT count(serverid) as num FROM servers WHERE owner_id = :useruid");
$result = $statement->execute();
echo $result;

But this does not work. The $result does not have the value 4 . Can you help me with that lines that are missing here?

Thank you very much.

Answer 1

First of all, you didn't bind your variable, so bind your variable using ->bindParam() first. And second, use ->fetch(PDO::FETCH_ASSOC) to get the row from the result set.

So your code should be like this:

$useruid = <YOUR VALUE>;

$pdo = new PDO('mysql:host=localhost;dbname=cswebin', 'root', 'password');
$statement = $pdo->prepare("SELECT count(serverid) as num FROM servers WHERE owner_id = :useruid");
$statement->bindParam(':useruid', $useruid);
if($statement->execute()){
    $row = $statement->fetch(PDO::FETCH_ASSOC);
    echo $row['num'];
}

Answer 2

You need to fetch the result after execute() the query. For example:

$result = $statement->execute()->fetchAll();

See http://php.net/manual/en/pdostatement.fetchall.php

Answer 3

Try it like this

$dt = $statement->execute();
$result = $dt->fetch();
var_dump($result);