获取URL中的最后一个数字

Question

How do I find the last number in a URL, from left to right?

For example:

https://www.portal-gestao.com/introducao-6849.html

Would return: 6849

And:

https://www.portal-gestao.com/curso-modelos-negocio/1452-introducao/6850-melhores-praticas-no-uso-de-folhas-de-calculo.html

Would return: 6850

This is what I'm trying:

EDIT: Updated code

jQuery('a.title').each(function () {
    var $link=jQuery(this);
    var href=$link.attr('href'); 
    var idx = href.indexOf('/')!=-1?1:0; // choose the second one if slash
    var procura=href.match(/(\d+)/g)[idx];

    jQuery.each(obj,function(_,test) {
        if(test.indexOf(procura)!=-1) { // only works on strings 
            ....
        }
    });
});

Answer 1

You can get the last number like following using regex .

function getLastNumber(url) {
    var matches = url.match(/\d+/g);
    return matches[matches.length - 1];
}

var url = 'https://www.portal-gestao.com/curso-modelos-negocio/1452-introducao/6850-melhores-praticas-no-uso-de-folhas-de-calculo.htm';
console.log(getLastNumber(url));

Answer 2

Here's a general solution that would give you the last number in a string (not necessarily a URL)

function getLastNumberOfString(str){
  var allNumbers = str.replace(/[^0-9]/g, ' ').trim().split(/\s+/);
  return parseInt(allNumbers[allNumbers.length - 1], 10);
}

Answer 3

This regex should do the job, it gets you the last number in the myString :

var myString = "https://www.portal-gestao.685com/introducao-6849.html";
var myRegexp = /(\d+)\D*$/g;
var match = myRegexp.exec(myString);
alert(match[1]);