[英]public Loader<Cursor> onCreateLoader(int id, Bundle args) method calling with several CursorLoader
TASK: I want to display a list of ListView and when you select an item to display the list of dialogue and display it in a list of another element (parent and child elements) 任务:我想显示一个ListView列表,当您选择一个项目以显示对话框列表并将其显示在另一个元素(父元素和子元素)的列表中时
static class GroupCursorLoader extends CursorLoader {
DB db;
public GroupCursorLoader(Context context, DB db) {
super(context);
this.db = db;
}
@Override
public Cursor loadInBackground() {
Cursor cursor = db.getGroupAll();
return cursor;
}
}
static class DetailCursorLoader extends CursorLoader{
DB db;
public DetailCursorLoader(Context context, DB db) {
super(context);
this.db = db;
}
@Override
public Cursor loadInBackground() {
Cursor cursor;
cursor = db.getDetailAll();
return cursor;
}
}
Now, The question is, how to handle the two Cursor? 现在,问题是,如何处理两个游标? , ie .
即。 written in the following methods
用以下方法写
public Loader onCreateLoader(int id, Bundle args)
公共加载程序onCreateLoader(int id,Bundle args)
public void onLoadFinished(Loader loader, Cursor data)
public void onLoadFinished(加载程序加载器,游标数据)
public void onLoaderReset(Loader loader)
公共无效onLoaderReset(Loader loader)
@Override
public Loader<Cursor> onCreateLoader(int id, Bundle args) {
return return new GroupCursorLoader(this, mDB);
}
@Override
public void onLoadFinished(Loader<Cursor> loader, Cursor data) {
scAdapterForGroup.swapCursor(data);
}
@Override
public void onLoaderReset(Loader<Cursor> loader) {
Log.d(LOG, "onLoadReset");
}
@Override
public Loader<Cursor> onCreateLoader(int id, Bundle args) {
if(id == GROUP_LOADER_ID) {
return new GroupCursorLoader(this, mDB);
} else {
return new DetailCursorLoader(this, mDB);
}
}
@Override
public void onLoadFinished(Loader<Cursor> loader, Cursor data) {
if(loader instanceof GroupCursorLoader) {
scAdapterForGroup.swapCursor(data);
} else {
scAdapterForDetails.swapCursor(data);
}
}
@Override
public void onLoaderReset(Loader<Cursor> loader) {
Log.d(LOG, "onLoadReset");
}
Answer question at ru.stackoverflow.com 在ru.stackoverflow.com上回答问题
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