[英]C realloc (dynamic arrays) - Access Violation
Starting out with dynamic arrays in C. I am getting an access violation when in the insertArray function (either in the realloc line or when trying to store the element (char) in the array. 从C中的动态数组开始。在insertArray函数中(在realloc行中或尝试将元素(char)存储在数组中时),我遇到访问冲突。
Can't seem to work around it or get to the bottom of it. 似乎无法解决它或触及它的底部。 Thanks
谢谢
Code: 码:
#include <stdio.h>
typedef struct {
char *array;
size_t used;
size_t size;
} Array;
Array elements;
void initArray(Array *a, size_t initialSize) {
a->array = (char *)malloc(initialSize * sizeof(char));
a->used = 0;
a->size = initialSize;
}
void insertArray(Array *a, char element) {
if (a->used == a->size) {
a->size *= 2;
a->array = (char *)realloc(a->array, a->size * sizeof(char));
}
a->array[a->used++] = element;
}
void popArray(Array *a) {
a->used--;
}
void freeArray(Array *a) {
free(a->array);
a->array = NULL;
a->used = a->size = 0;
}
char vars[15];
int main() {
initArray(&elements, 2);
printf("Enter 15 character String: ");
scanf_s("%s", vars, 15);
for (int i = 0; i < 15; i++) {
insertArray(&elements, vars[i]);
}
freeArray(&elements);
}
I suspect the problem is caused by the missing #include <stdlib.h>
. 我怀疑问题是由缺少的
#include <stdlib.h>
引起的。
See Do I cast the result of malloc? 请参见是否强制转换malloc的结果? to understand why you should not cast the return value of
malloc
. 了解为什么不应该
malloc
的返回值。
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