IPython 脚本 - 使用状态代码退出脚本

Question

I am trying to use ipython to script git pre-commit hooks since it has a nice syntax to run shell commands and converting the stdout result into a list of strings (which makes for easy processing).

I need to return a status code != 0 from the ipython script so that git pre-commit hook will abort the commit.

Consider this example script

#! /bin/ipython
import sys
sys.exit(1)

running it from the shell

$ ipython test.ipy

but then checking the status code with $ echo $? always returns 0

Is there a way to make ipython return a non-zero status code?

Answer 1

Open up ipython and try running that code interactively.

In [1]: import sys
In [2]: sys.exit(1)

An exception has occurred, use %tb to see the full traceback.

SystemExit: 1

To exit: use 'exit', 'quit', or Ctrl-D.

So, ipython is catching the SystemExit exception. I would suggest using a different interpreter for this particular job, nice as ipython is. Alternatively you can use:

import os
os._exit(1)

However, this skips all sorts of important cleanup code (eg finally blocks) and is generally a Bad Idea.

Edit:

This seems to work. After writing it I can hear some alarm bells in the distance and there are red flags waving. Not sure what that's about. Anyway, create a new script /usr/bin/ipysh with:

#!/usr/bin/python

import sys
from IPython.core import interactiveshell
shell = interactiveshell.InteractiveShell()
shell.safe_execfile(sys.argv[1], {}, raise_exceptions=True,
                    exit_ignore=False)

Make that executable, then set your hook's hashbang to #!/usr/bin/ipysh .