[英]Distinct List<List<int>>?
I have a problem with getting only the distinct lists. 我仅获取不重复列表有问题。
So I have : 所以我有 :
List<List<int>> combinations = new List<List<int>>();
combinations.Add(new List<int> {1,1});
combinations.Add(new List<int> {1,2});
combinations.Add(new List<int> {1,1}); // Same
combinations.Add(new List<int> {1,3});
What I need to do is to get only : 我需要做的只是获得:
{1,1}
{1,2}
{1,3}
I tried with this : combinations = combinations.Distinct().ToList();
我尝试过这样的方法: combinations = combinations.Distinct().ToList();
But it does not work. 但这行不通。
Any ideas. 有任何想法吗。 Thank you in advance. 先感谢您。
You can use your own comparer: 您可以使用自己的比较器:
var distincts =
combinations
.Distinct(new ListOfIntComparer());
class ListOfIntComparer : IEqualityComparer<List<int>>
{
public bool Equals(List<int> a, List<int> b)
{
return
a.SequenceEqual(b);
}
public int GetHashCode(List<int> l)
{
unchecked
{
int hash = 19;
foreach (var foo in l)
{
hash = hash * 31 + foo.GetHashCode();
}
return hash;
}
}
}
GetHasCode()
implementation from Jon Skeet here . GetHasCode()
从乔恩斯基特执行这里 。
Trying to come up with the shortest oneliner. 试图提出最短的oneliner。 This is what i come up with. 这就是我想出的。 Hope it helps you. 希望对您有帮助。
var unique = combinations.GroupBy(x => string.Join(",", x), (g, items) => items.First());
Try adding a regular int array: 尝试添加常规的int数组:
List<List<int>> lli = new List<List<int>>();
lli.Add((new int[] { 2, 4 }).ToList<int>());
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