骆驼：RabbitMQ to SOAP：重新排队

Question

I am learning Apache camel and trying to send request from RabbitMQ endpoint to some soap service :

<camelcontext>
route 1 from file:// to rabbitmq queue 
<route id="2">
<from uri="same queue as in route 1"/>
<process "here i am setting header "/>
<pattern>InOut</pattern>
<to uri="soap request"/>
</camelcontext>

What I want is that in case there is any exception at SOAP, exchange should be requeued back to rabbitmq. I have tried setting header of exchange rabbitmq.REQUEUE to true still no luck, message gets removed even though there is exception. I have tried setting exchange to InOUT too. Please suggest any pointer.

Answer 1

To catch an exception coming back from calling the SOAP service you could use an onException to catch the fault and then route it to rabbitMQ queue like this:

onException(Fault.class).handled(true)
    .to("rabbitmq:queue-name")