如何在Node JS中接受大量的API请求

Question

I recently started learning Node JS. And things went pretty well. I saw an online tutorial and accepted GET request in my server.js file.

Since I'm from a Java background, a few questions arrived into my mind and I searched them all over the Internet but could not find them out.

1. Do I need to accept all my requests within request.js file. Suppose if I have hundreds of GET api requests do I need to write them in my server.js file which I feel is the only entry point in Node JS.

For Example:

var express=require("express");
var app=express();
app.get("/api/request1/",function(){
    //some code here
})
app.get("/api/request2/",function(){
    //some code here
})
.
.  
.
.
app.get("/api/request100/",function(){
    //some code here
})

This would make my code cumbersome and difficult to manage. As I said I have a Java background and I used to separate my code in different Servlets.

2. Secondly is it possible to have another entry point in Node JS. Since my application is quite big. Also is there a way to use Node Modules to segregate/separate my code within different modules and then include them in server.js.

Please specify some good resource or a technique how to overcome this issue.

Answer 1

You can easily modularize your express routes.

To follow your example: in your project, create a directory routes and a file routes/api.js with the following contents:

var express = require('express');
var router = express.Router();

router.get('/request1', function(req, res, next) {
  res.send('...');
});
router.get('/request2', function(req, res, next) {
  res.send('...');
});

module.exports = router;

And in your server.js :

app.use('/api', require('./routes/api'));

Just in case someone has the same question you can refer to the Express routing documentation

Answer 2

app.get(...) is just a function call. You can easily do this:

require('routes1')(app);
require('routes2')(app);

where those modules export function(app) { app.get(...); app.get(...); } function(app) { app.get(...); app.get(...); }

Even better, Express.js (not Node.js - Node.js is like JVM, Express is like Tomcat) apps can mount subapps:

app.use('/api', require('subapp'));

If subapp is a normal Express.app with, say, app.get('/request1', ...) , then, after mounting, you will have /api/request1 available to you. (This only works for entire hierarchies; so if you want to split your /api/request1 ... /api/request100 into ten files, you might want to use the first approach, or rethink how your hierarchy works.)

Answer 3

是的，您应该与模块尽可能保持隔离，因为我看到您已经开始学习express do checkout express-generator模块，该模块为您提供一个不错的小型样板代码，在构造大型项目时也要从中开始列出Blog best-practices-express-结构以进行高级使用