[英]Weird Android intent-filter pathPattern issue while deep linking
I want to create deeplinks for these two http urls 我想为这两个http网址创建深层链接
https://sample-app-123.appspot.com/backoffice/#/user_reset_password?email=abc@gmail.com https://sample-app-123.appspot.com/backoffice/#/user_create_password?email=abc@gmail.com
https://sample-app-123.appspot.com/backoffice/#/user_reset_password?email=abc@gmail.com https://sample-app-123.appspot.com/backoffice/#/user_create_password?email=abc @ gmail.com
I have gone through various StackOverflow answers, none of them worked. 我经历了各种StackOverflow答案,但没有一个起作用。 I got to know PatternMatcher.PATTERN_SIMPLE_GLOB is used by Android for matching pattern instead of regex expressions.
我知道PatternMatcher.PATTERN_SIMPLE_GLOB被Android用于匹配模式而不是正则表达式。
My manifest looks like 我的清单看起来像
<activity android:name=".CreateActivity"
android:label="Create Password"
>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.VIEW"/>
<category android:name="android.intent.category.DEFAULT"></category>
<category android:name="android.intent.category.BROWSABLE"></category>
<data
android:host="sample-app-123.appspot.com"
android:scheme="https"
android:pathPattern=".*create_password.*"
/>
</intent-filter>
</activity>
<activity android:name=".ResetActivity"
android:label="Reset Password"
>
<intent-filter>
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.VIEW"/>
<category android:name="android.intent.category.DEFAULT"></category>
<category android:name="android.intent.category.BROWSABLE"></category>
<data
android:host="sample-app-123.appspot.com"
android:scheme="https"
android:pathPattern=".*reset_password.*"
/>
</intent-filter>
</activity>
I have created several tests for checking PatternMatcher.PATTERN_SIMPLE_GLOB , All tests are PASSED, i am clueless why its not working 我创建了一些测试来检查PatternMatcher.PATTERN_SIMPLE_GLOB ,所有测试都通过了,我不知道为什么它不起作用
public void testPatternMatcher() throws Exception {
PatternMatcher mPatternMatcher;
mPatternMatcher = new PatternMatcher("https://sample-app-123.appspot.com/backoffice\\/#\\/user_create_password.*", PatternMatcher.PATTERN_SIMPLE_GLOB);
assertTrue(mPatternMatcher.match("https://sample-app-123.appspot.com/backoffice/#/user_create_password?email=abc@gmail.com"));
assertFalse(mPatternMatcher.match("https://sample-app-123.appspot.com/backoffice/#/user_reset_password?email=abc@gmail.com"));
mPatternMatcher = new PatternMatcher(".*user_create_password.*", PatternMatcher.PATTERN_SIMPLE_GLOB);
assertTrue(mPatternMatcher.match("https://sample-app-123.appspot.com/backoffice/#/user_create_password?email=abc@gmail.com"));
assertFalse(mPatternMatcher.match("https://sample-app-123.appspot.com/backoffice/#/user_reset_password?email=abc@gmail.com"));
mPatternMatcher = new PatternMatcher(".*user_reset_password.*", PatternMatcher.PATTERN_SIMPLE_GLOB);
assertFalse(mPatternMatcher.match("/backoffice/#/user_create_password?email=abc@gmail.com"));
assertTrue(mPatternMatcher.match("/backoffice/#/user_reset_password?email=abc@gmail.com"));
}
create_password
or reset_password
are not part of the uri path. create_password
或reset_password
不属于uri路径。
The uri path ends just before the #
character. uri路径在
#
字符之前结束。 This is a special character that delimits the query
from the hash
(or anchor). 这是一个特殊字符,用于从
hash
(或锚点)中分隔query
。
scheme: https://
方案:
https://
host: sample-app-123.appspot.com
主持人:
sample-app-123.appspot.com
path: /backoffice/
路径:
/backoffice/
fragment #/user_reset_password?email=abc@gmail.com
片段
#/user_reset_password?email=abc@gmail.com
You should instead use url like: 您应该改用如下网址:
https://sample-app-123.appspot.com/backoffice/user_reset_password?email=abc@gmail.com
https://sample-app-123.appspot.com/backoffice/user_create_password?email=abc@gmail.com
This will work as expected. 这将按预期工作。
scheme: https://
方案:
https://
host: sample-app-123.appspot.com
主持人:
sample-app-123.appspot.com
path: /backoffice/user_create_password
路径:
/backoffice/user_create_password
query: email=abc@gmail.com
查询:
email=abc@gmail.com
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.