从C中的txt文件解析和拆分字符串

Question

I'm new into C and I got an assignment to read line by line from .txt file and parse some strings into matrix where first line is first row, second line is second row etc. This is what I have in my text.txt file:

07 45 C4 16 0F 02 19 0I 17 0G 
09 45 C4 15 0E 03 11 0A 12 0B 13 0C
13 45 C4 13 0C 03 19 0I 11 0A 17 0G 14 0D 16 0F
05 45 C4 18 0H 01 12 0B

This is what I was able to do so far:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char *Read(char filename[]);

void split(char *content);

int main(void){

    char filename[] = "text.txt";
    char *content = Read(filename);
    split(content);
    return 0;
}

char *Read(char filename[]){

    char *buffer;
    long size;

    FILE *log = fopen("text.txt", "r");
    fseek(log, 0, SEEK_END);
    size = ftell(log);
    rewind(log);

    buffer = (char*) malloc(sizeof(char) * size);
    fread(buffer, 1, size, log);
    fclose(log);

    return buffer;
}

void split(char *content){

    char *buffer = strtok(content, " ");
    while(buffer != NULL){
        printf("%s\n", buffer);
        buffer = strtok (NULL, " ");
    }
}

I would really appreciate comments in code because I'm rookie and it would help me to better understand some things.

Answer 1

To give you an idea of how it works, I wrote this snippet which manually read the line in that array, supposing that we already know the desired results.

The following approach cannot be considered the right one. Ideally you would have a series of rules to split the string, in the following however you have to set the scanf format manually for each line that you want to read.

Remember to check the return value of scanf, here we should ensure that we have read 7 elements.

int main(void) {
    FILE *log;
    char buffer[SIZE];
    char line[SIZE];

    char array[10][10];

    if ((log = fopen("text.txt", "r")) == NULL){
        fprintf(stderr, "Can't open input file!\n");
        return(1);
    }

    while(fgets(buffer, sizeof(buffer), log)){
        int ret = sscanf(buffer, "%2s%2s%2s%4s%2s%4s%4s", array[0], array[1], array[2], array[3], array[4],array[5], array[6]);
        printf("read %d elements\n", ret);
        if (ret != 7) {
           return(1);
        }
        printf("%s", buffer);
    }

    int i;
    for (i=0; i < 6; i++)
        printf("%s\n", array[i]);

    fclose(log);

    return 0;
}