[英]Javascript Code improvement - Integer factorial
I am learning to code with Javascript and one exercise is about returning the factorial of a provided integer. 我正在学习使用Javascript进行编码,一种练习是关于返回提供的整数的阶乘。 For example: 5!
例如:5! = 1 * 2 * 3 * 4 * 5 = 120
= 1 * 2 * 3 * 4 * 5 = 120
I came up with a result and it was accepted. 我想出了一个结果,它被接受了。 However, I am not so sure it would be the most efficient way of solving this.
但是,我不确定这将是解决此问题的最有效方法。
Anyone would have any tips on how to improve this code? 任何人都将对如何改进此代码有任何提示?
function factorialize(num) {
var array = [];
for (i = 1; i <= num; i++) {
array.push(i);
}
var multi = 1;
for (var i = 1; i < array.length; i++) {
multi *= array[i];
}
return multi;
}
Many thanks!! 非常感谢!!
You have several approaches to get a solution. 您有几种解决方案。
by iteration 通过迭代
function f(n) { var r = n; while (--n) { r *= n; } return r; }
by recursion 通过递归
function f(n) { return n === 0 ? 1 : n * f(n - 1); }
or a very short version 或非常简短的版本
function f(n) { return +!~-n || n * f(n - 1); }
Why don't you use 你为什么不使用
var ans=1;
for (i=1;i<=num;i++)//for(i=num;i>=1;i--)
{
ans=ans*i;
}
return ans;
I have used this kind of recursive method 我已经使用了这种递归方法
function f(p) {
if (p==1) return;
p -= 1;
x = x * p;
f(p);
}
A corrected version (with comments) : 更正的版本(带有注释) :
function f(p) {
if (p == 0) return 1; /* 0! == 1 by definition, */
return p * f(p - 1); /* otherwise p! = p * (p-1)! */
}
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