通过NOT包含字符串过滤数组（swift 2）

Question

I am relatively new to swift; I am working on filtering arrays. I know how to filter out elements of an array that contain a letter (like so: let filteredList = wordlist.filter { !$0.characters.contains(letter) } ), but how do I filter out elements that do not have a letter? Here's what I want to accomplish: I have a word list in string-array format, ie ["thing", "other thing"] (but much longer), and I want to return every element that has a certain letter, filtering out the ones that do not have a certain letter.

Thanks in advance.

Answer 1

This was a silly question, I am sorry. Anyway, I just needed to remove the exclamation mark. So...

let filteredList = wordlist.filter { !$0.characters.contains(letter) } 
// returns elements in the array WITHOUT "letter".
let filteredList = wordlist.filter { $0.characters.contains(letter) }  
// returns elements in the array WITH "letter".

Thanks Eendje.