[英]Count number of rows with conditions met in multiple columns
I can use 我可以用
=COUNTIFS(range1, criteria1, range2, criteria2…) + COUNTIFS(...) etc
Count number of rows with conditions met in two columns 计算两列中满足条件的行数
My data is such that the above will require needing approximately 150+ instances of countifs just for one cell. 我的数据是这样的,以上仅需要为一个单元格需要大约150多个countif实例。 And I need to do this for 10K or so cells. 我需要对10K左右的单元格执行此操作。 So wondering if there is another function/way to do this in a more efficient manner? 因此,想知道是否还有另一种功能/方式可以更有效地做到这一点? Example of data as follows; 数据示例如下;
1 2 10 6
2 3 9 4
3 4 8 5
7 6 7 2
4 5 1 6
2 1 6 7
5 6 2 8
2 5 3 10
6 7 2 10
And need to count how many times number 2 & 6 occur on the same row. 并且需要计算2和6在同一行上出现了多少次。
EDIT: I also need to do this with any number combination. 编辑:我还需要使用任何数字组合来执行此操作。 ie 2&6, 1&6, 5&10 etc. 即2&6、1&6、5&10等。
Thanks 谢谢
Add a column with a serial no from 1 to n. 添加一个序列号从1到n的列。
Then use a nested if: 然后在以下情况下使用嵌套:
SUM(IF(SERIAL_NO = SERIAL NO
IF( IF COLUMN1 =2 AND COLUMN 3 = 6,10))) AS 26
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