[英]Regex to Match a bunch of character + only a single |
I have a regex that works great for matching the following.. 我有一个正则表达式非常适合匹配以下内容。
^[a-z-&+/]
Now I want add in a match for the "|" 现在,我要为“ |”添加一个匹配项 symbol, but only if it starts with a single "|" 符号,但前提是它以单个“ |”开头
True results 真实结果
|hello
apple
test||test
False Results 错误的结果
||hello
I tried a bunch of ways on regex101.com - but I can't come up with the right regex. 我在regex101.com上尝试了多种方法-但我无法提出正确的regex。
This regex works for what you want: 此正则表达式适用于您想要的:
^([a-z-&+\/]|\|(?!\|))
This goes from the start of the input, tries to find any of your original characters ( [az-&+/]
) OR a |
这从输入的开头开始,尝试查找您的任何原始字符( [az-&+/]
)或|
not followed by a |
后面没有|
(using a negative lookahead). (使用负前瞻)。
See a demo on regex101.com . 参见regex101.com上的演示 。
This worked for me: 这为我工作:
/^[|a-z-&+/](?!\|)/
One can use | 一个可以使用 inside character set as well. 内部字符集。 Check http://www.regexr.com/3coad where i tested the match. 检查http://www.regexr.com/3coad我在哪里测试了比赛。
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