[英]How do I add white space in regex?
I have this code: 我有以下代码:
CODE JS: 代码JS:
const phone= /^\(?(\d{3})\)?[-]?(\d{3})[-]?(\d{4})$/;
After running this code has the following form 运行此代码后具有以下形式
(123)132-1312
I want to add white space before the last parentheses as in the example below. 我想在最后一个括号之前添加空格,如下例所示。
(123 )132-1312
Can you please tell me how to accept changes to the code so that white space? 能否请您告诉我如何接受对代码的更改,使空格为空白?
Thanks in advance! 提前致谢!
EDIT: 编辑:
text = $(this).val().replace(/(\d{3})(\d{3})(\d{4})/, "($1)$2-$3");
var testt=$(this).val().match(text);
I added this code to call here as add white space ... 我添加了此代码以在此处调用以添加空格...
这应该可以根据需要工作:
/^\(?\s*(\d{3})\s*\)?[-]?(\d{3})[-]?(\d{4})$/
Depending on wether you always want the whitespace befor the closeing parenthesis or not your could go with: 根据不同的情况,您始终希望空格位于右括号之间,或者不可以:
^\\(?(\\d{3}\\s?)\\)?[-]?(\\d{3})[-]?(\\d{4})$
Background \\s
is for whitespaces. 背景\\s
用于空格。 the ?
?
stands for 0 or 1 occurrance of the previous sign. 代表前一个符号出现0或1。 if you use +
it is one or more and *
is for 0 or more occurrences of the previous sign. 如果使用+
,则表示一个或多个,而*
表示0个或多个出现的前一个符号。
To test your regex you can always use regexpal 要测试你的正则表达式,你可以随时使用regexpal
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