[英]MySQL SELECT query result to JSON
I have a model which runs the following SELECT query. 我有运行以下SELECT查询的模型。
MODEL 模型
public function get_details($start, $limit) {
$sql = $this->db->query("SELECT E.`exam-id` AS `examid`, T.`topic-name` AS `topic`,E.`date`, COUNT(E.`exam-id`) AS `total` FROM `exam` E, `exam-topic` T WHERE E.`exam-dbname`=T.`topic-dbname` GROUP BY `exam-id` ORDER BY `exam-id` DESC LIMIT $start, $limit;");
if($sql->num_rows() > 0){
return $sql;
}
else{
return FALSE;
}
}
MY CONTROLLER 我的控制器
public function get_details() {
//pagination
$config = array(
'base_url' => base_url()."exam/create/created/index",
'total_rows' => $this->exam->get_total(),
'first_link' => "First",
'last_link' => "Last",
'per_page' => 2,
'uri_segment' => 5,
'full_tag_open' => "<div class='paginate'>",
'full_tag_close' => "</div>",
'num_tag1_open' => '<a>',
'num_tag1_close' => '</a>',
'cur_tag_open' => "<a class='current'>",
'cur_tag_close' => "</a>",
'next_tag1_open' => "<a>",
'next_tag1_close' => "</a>",
'prev_tag1_open' => "<a>",
'prev_tag1_close' => "</a>",
'first_tag1_open' => "<a>",
'first_tag1_close' => "</a>",
'last_tag1_open' => "<a>",
'last_tag1_close' => "</a>"
);
$page=($this->uri->segment(5) != '') ? $this->uri->segment(5) : 0;
$this->pagination->initialize($config);
$data = array(
'query' => $this->exam->get_details($page, $config['per_page']),
'links' => $this->pagination->create_links()
);
echo json_encode($data);
}
In the view page, I use AJAX to catch the result. 在视图页面中,我使用AJAX捕获结果。
MY VIEW 我的观点
function get_details() {
$.ajax({
url : "<?php echo base_url(); ?>exam/create/created/get_details.html",
dataType: "JSON",
success : function(data) {
var obj = $.parseJSON(data.query);
$.each(obj, function(key, val) {
alert(key+"\n"+val.uid);
});
}
}); }
Now, I don't have a clue how to get the results of data[query]
in the JSON as data[query]
holds multiple results returned by MySQL. 现在,我不知道如何在JSON中获取data[query]
的结果,因为data[query]
包含MySQL返回的多个结果。
Thanks in advance. 提前致谢。
In your controller code should be. 在您的控制器中应该是代码。
$data = array(
'query' => json_encode($this->exam->get_details($page, $config['per_page'])),
'links' => $this->pagination->create_links()
);
echo json_encode($data);
because you are parsing data.query using json parse so data that you are getting from database should be json. 因为您正在使用json parse解析data.query,所以从数据库获取的数据应为json。
Thanks Amit 谢谢阿米特
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