如何在不获取JSHint问题的情况下扩展javascript字符串？

Question

Hi I am extending String using prototype but JSHint throws a warning:

Extending prototype of native object: 'String'.

How should I be tackling this? I assume the warning is down to this method being considered bad practice.

String.prototype.decodeHTML = function() {

    return $('<div>', {html: '' + this}).html();

};

Any help would be greatly appreciated, thanks.

UPDATE This does actually work:

Here's the solution for those that want it.

Object.defineProperty(String.prototype, "decodeHTML", {
    value: function () {
         return $('<div>', {html: '' + this}).html();
    }
});

Answer 1

See JSLint Docs: https://jslinterrors.com/extending-prototype-of-native-object . You should use

Object.defineProperty(String.prototype, "decodeHTML", ...)

instead.

Answer 2

The warning in question should only be issued when the freeze option is enabled. You can disable that option for the relevant block (or file) by using a directive comment:

/*jshint freeze: false */
String.prototype.decodeHTML = function() {

    return $('<div>', {html: '' + this}).html();

};