C＃正则表达式不匹配-应该何时存在

Question

I'm trying to match 0 or more strings of letters, numbers, and white space between quotation marks ("), these sets can be separated by white space or not, and the string will start with a key word to identify what to do with the matched sets.

The simplest example is below:

\\ inString = test "1" "a""3";
Regex regEx = new Regex("@(\"[0-9 a-z]*\")", RegexOptions.IgnoreCase);
Match match = regEx.Match(inStr);

The match is not a success, let alone containing the 3 expected results

However via http://regexhero.net the match is a success - I'm using regexhero as its SilverLight based so is using the .NET Regex engine...

Regexhero settings:

Regular Expression

(\"[0-9 a-z]*\")

Target String

test "1" "b""3"

Result

1: "1"
1: "b"
1: "3"

Can anyone explain whats wrong with my implementation?

Answer 1

I expect your regex is meant to be:

Regex regEx = new Regex("(\"[0-9 a-z]*\")", RegexOptions.IgnoreCase);

or (exactly the same)

Regex regEx = new Regex(@"(""[0-9 a-z]*"")", RegexOptions.IgnoreCase);

It looks like this question might be a fruitful read for you:

What's the use/meaning of the @ character in variable names in C#?

Answer 2

You must change the regexp patern:

"@(\"[0-9 a-z]*\")"

to

@"(""[0-9 a-z]*"")"

Also You need change

Match match = regEx.Match(inStr);

to

MatchCollection match = regEx.Matches(intstr); 

Because Matches searches an input string for all occurrences of a regular expression and returns all the matches but Match searches the specified input string for the first occurrence of the regular expression

If You want result like this:

1: "1"
1: "b"
1: "3"

You need to change to Matches