[英]JS add attribute to string
I have a post ajax that return retorno1
and just to get it simple i put their output as string value as ajax posted like the example .. then I need to add more than 1 option that the value is 0 so I need to say if the value is 0 show the selected item "NON" and if the value other so show it and select it. 我有一个返回
retorno1
的ajax retorno1
,只是为了简单retorno1
,我将它们的输出作为字符串值作为ajax发布,例如示例..然后我需要添加多个选项,该选项的值是0,所以我需要说一下如果值为0,则显示所选的项目“ NON”;如果其他值为,则显示并选择它。
I'm using setAttribute("selected", "selected")
but I know it's wrong, so what is the correct code to add attribute to this string? 我正在使用
setAttribute("selected", "selected")
但我知道这是错误的,那么将属性添加到此字符串的正确代码是什么?
var i = 0;
var returno1 = "<option value='21'>Hello</option><option value='22'>Bye</option>";
var pre = retorno1 + '<option value="0">------ N/A ------</option>';
var count = $($.parseHTML(pre)).filter('option').length;
var dep_dr = $("#departamento_drop option:selected").val();
$.each($.parseHTML(pre),function(i,item){
var val_drop =($(item).val());
var text_drop =($(item).html());
if (val_drop == dep_dr){
jQuery("#departamento_drop").html(pre).setAttribute("selected", "selected");
}else if(dep_dr == "0"){
jQuery("#departamento_drop").html(pre).setAttribute("selected", "selected");
}
})
Try to use attr()
or prop()
to set or get attribute to elements, check example bellow : 尝试使用
attr()
或prop()
来设置或获取元素的属性,请检查以下示例:
jQuery("#departamento_drop").empty();
$.each($.parseHTML(pre),function(i,item){
var current_itme=$(item);
var val_drop =current_itme.val();
var text_drop =current_itme.html();
if (val_drop == dep_dr || dep_dr == "0"){
current_itme=current_itme.attr("selected", "selected");
}
jQuery("#departamento_drop").append(current_itme);
})
Hope this helps. 希望这可以帮助。
Why do you need use strings? 为什么需要使用字符串? Use objects insted.
使用插入的对象。
var values = [{val:33, title:'Hi'},{val:34, title:'Bue'},{val:0, title:'-------NA-------'}],
selected = 34;
values.forEach(function(item){
$('#dd').append($('<option>', {value:item.val, text:item.title, selected: item.val==selected}));
})
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.