使用扩展的用户模型，如何在同一视图中创建具有两个模型形式的两个模型实例？

Question

First off, I want to say that I am new to django though I understand most of it, forms have always been confusing to me.

I have two models in which I need to create an instance from, the standard built in User model and my own UserProfile model.

The problem I am facing is that really do not know how to display two forms (one for each model) in the template and on save() then tell django that the newly created UserProfile instance's User = model.ForeignKey belongs to the also newly created User .

My forms.py is fairly simple:

from django import forms
from django.forms import ModelForm
from django.contrib.auth.models import User
from .models import UserProfile

class UserForm(ModelForm):

    class Meta:
        model = User
        fields = ('username', 'email', 'password')

class  UserProfileForm(ModelForm):

    class Meta:
        model = UserProfile
        fields = ('display_name', 'avatar', 'birthday', 'usertype', 'daw', 'usergenre')

In my views.py I've tried doing this:

from .forms import UserForm
from .forms import UserProfileForm

# Create your views here.
def RegisterView(request):
    if request.method == 'POST':
        form = UserForm(request.POST)
        form2 = UserProfileForm(request.POST)
        if form.is_valid():
            if form2.is_valid():
                return HttpResponseRedirect('/login/')

    return render(request, 'register.html', {'form': form, 'form2': form})

But when I try to access /register I get this error: http://dpaste.com/19NH2A6

Answer 1

You should use save() method. Next time you have a problem, check the official Django documentation. ModelForms - save() method

from .forms import UserForm
from .forms import UserProfileForm
from django.http import HttpResponseRedirect


def RegisterView(request):
    if request.method == 'POST':
        form = UserForm(request.POST, prefix='uf')
        form2 = UserProfileForm(request.POST, prefix='upf')
        if form.is_valid():
            if form2.is_valid():
                form.save()
                form2.save()
                return HttpResponseRedirect('/login/')
    elif request.method == 'GET':
        form = UserForm(prefix='uf')
        form2 = UserProfileForm(prefix='upf')            

    return render(request, 'register.html', {'form': form, 'form2': form2})

Answer 2

When you hit /register page from browser, your view gets GET request, you have created form only for POST request

from .forms import UserForm
from .forms import UserProfileForm

# Create your views here.
def RegisterView(request):
    if request.method == 'POST':
        form = UserForm(request.POST, prefix='uf')
        form2 = UserProfileForm(request.POST, prefix='upf')
        if form.is_valid():
            if form2.is_valid():
                return HttpResponseRedirect('/login/')
    elif request.method == 'GET':
        form = UserForm(prefix='uf')
        form2 = UserProfileForm(prefix='upf')            

    return render(request, 'register.html', {'form': form, 'form2': form2})

Answer 3

You should read the traceback yourself so that you can find the error easily. It says;

Exception Type: NameError at /register/ Exception Value: name 'HttpResponseRedirect' is not defined

You've used HttpResponseRedirect but you didn't import it, therefore it is not defined.

Add this to top of your code.

from django.http import HttpResponseRedirect