[英]Sum of columns with partial string match, with names imported from a list. R
I'm working with data tables like so: 我正在使用这样的数据表:
ID <- c("ChrM","ChrM","ChrM","ChrM","ChrM")
pos <- c(5,6,7,10,11)
cr.H.MN.8A <- c(0,0,3,0,1)
cr.H.MN.8B <- c(2,1,0,1,0)
cr.H.MR.8A<-c(0,0,0,0,1)
cr.H.MR.8B<-c(0,2,0,0,1)
cr.H.MR2.8A<-c(0,1,1,0,0)
cr.H.MR2.8B<-c(0,1,0,0,0)
dfa <- data.table(ID,pos,cr.H.MN.8A,cr.H.MN.8B,cr.H.MR.8A,cr.H.MR.8B,cr.H.MR2.8A,cr.H.MR2.8B)
dfa
ID pos cr.H.MN.8A cr.H.MN.8B cr.H.MR.8A cr.H.MR.8B cr.H.MR2.8A cr.H.MR2.8B
1: ChrM 5 0 2 0 0 0 0
2: ChrM 6 0 1 0 2 1 1
3: ChrM 7 3 0 0 0 1 0
4: ChrM 10 0 1 0 0 0 0
5: ChrM 11 1 0 1 1 0 0
>
Now, on an earlier question I asked how I could use the similiraties on the name strings to add them up 现在,在一个较早的问题上,我问我如何使用名称字符串上的相似性将它们加起来
dfa[,`H.MN.8` := as.numeric(rowSums(.SD) > 1), .SDcols = grep("cr.H.MN.8", names(dfa))]
Which worlks flawlessly. 完美无瑕的蠕动。 But I got another question; 但是我还有另一个问题。 is it possible to auto assign the parameters needed to separate the string? 是否可以自动分配分隔字符串所需的参数? I've got the names of each column on a list (they used to be different data.frames), so could I use it to replace the HM.MN.8
and thus make it more easily computed? 我在列表上有每一列的名称(它们以前是不同的data.frames),所以我可以用它代替HM.MN.8
,从而使计算更容易吗? Thanks! 谢谢!
The names are so: 名称如下:
names(dfb)<-c("cr.H.MN.8A","cr.H.MN.8B","cr.H.MR.8A","cr.H.MR.8B","cr.H.MR2.8A","cr.H.MR2.8B")
you can try using 你可以尝试使用
varName <- c("H.MR2","H.MN.8")
eval(parse(text=paste0("dfa[,`",varName,"` := as.numeric(rowSums(.SD) > 1), .SDcols = grep('",varName,"', names(dfa))]")))
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