Java：对可重定位对象的引用如何工作？

Question

By relocatable objects, I mean objects that can relocate itself in memory when there is not enough consecutive space. (for example ArrayList)

 List<String> list1 = new ArrayList<>();
 List<String> list2 = list1;

If I keep adding things to list1, it will eventually relocate because there is not enough continuous address space. Then will list2 and list still point to the same address or not? If so, how is it done underneath?

Answer 1

No object can relocate itself. What happens here is that list1 and list2 point to the same object and this object (ie the ArrayList ) contains another reference to the actual storrage (ie the array that is used to store the data). If the list grows too big, the pointer to the storrage array changes, not the location of the ArrayList object itself.