致命错误：TableView中的数组索引超出范围

Question

hello I have a Dynamic Prototype TableView. I have added 4 prototype cells. Three are static and one is dynamic. The problem is I am getting Array index out of range error. could you please check what went wrong. what should be the total number of rows should I assign

let NUMBER_OF_STATIC_CELLS = 3
var labels = ["label1","label2","label3"]

override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {


    return labels.count+NUMBER_OF_STATIC_CELLS



}

override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
    return 1
}
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {



    var cell:  TestViewCell!

    print(indexPath.row)
    if (indexPath.row == 0) {
        cell = tableView.dequeueReusableCellWithIdentifier("static1", forIndexPath: indexPath) as! TestViewCell


    }

    if (indexPath.row == 1) {
            cell = tableView.dequeueReusableCellWithIdentifier("static2", forIndexPath: indexPath) as! TestViewCell
        //cell.cardSetName?.text = self.cardSetObject["name"] as String
        }

     if (indexPath.row == 2) {
            cell = tableView.dequeueReusableCellWithIdentifier("static3", forIndexPath: indexPath) as! TestViewCell
            //cell.cardSetName?.text = self.cardSetObject["name"] as String
        }




      if (indexPath.row >= 3) {

        cell = tableView.dequeueReusableCellWithIdentifier("cell", forIndexPath: indexPath) as! TestViewCell
        cell.testLabel.text = labels[indexPath.row] // return test rows as set in numberOfRowsInSection
    }

    return cell;
   }

Answer 1

You have set that number of cells will be 6 and in labels array you have only 3 elements. Moreover in each condition you are assigning to cell but at the end of the method you are overwriting that assignment which is (I suppose) not your intention. Then you are trying to access element under the index that is out of bounds

Answer 2

This is your ERROR! You have no label with an index above 2. The line below tries to do to label[3] etc.

cell.testLabel.text = labels[indexPath.row]