[英]Go : format struct for javascript (json without keys)
I have to form a slice of structs for the chart. 我必须为图表形成一部分结构。 Marshal it, and return to the frontend widget.
封送它,然后返回到前端小部件。 Widget is waiting for the format like this :
窗口小部件正在等待这样的格式:
[["1455523840380",1],["1455523840383",2],["1455523840384",3]]
But My data comes like this : 但是我的数据是这样的:
[{"Time":1.45552462158e+12,"Value":1},{"Time":1.45552462158e+12,"Value2},{"Time":1.45552462158e+12,"Value3}]
My struct that is coming to the slice is made like this : 我的切片结构如下所示:
type ChartElement struct {
Time int `json:""`
Value int `json:""`
}
I have now 2 main troubles: 我现在有两个主要的麻烦:
The output format you want: 您想要的输出格式:
[["1455523840380",1],["1455523840383",2],["1455523840384",3]]
In JSON it is not an array of struct, but an array of arrays. 在JSON中,它不是结构数组,而是数组数组。
Since the "internal" array has various types (string and numeric), you can model it like this: 由于“内部”数组具有各种类型(字符串和数字),因此可以像下面这样建模:
type ChartElement []interface{}
And you can populate it like this: 您可以像这样填充它:
s := []ChartElement{{"1455523840380", 1}, {"1455523840383", 2}, {"1455523840384", 3}}
And if you marshal it to JSON: 如果将其封送为JSON:
data, err := json.Marshal(s)
fmt.Println(string(data), err)
Output is what you expect: 输出是您期望的:
[["1455523840380",1],["1455523840383",2],["1455523840384",3]] <nil>
And the time values such as 1455523840380
are the the number of milliseconds elapsed since January 1, 1970 UTC. 时间值(例如
1455523840380
是自1970年1月1日UTC以来经过的毫秒数。 In Go you can get this value from a time.Time
value with its Time.UnixNano()
method and dividing it by 1000000
(to get milliseconds from nanoseconds), for example: 在围棋,你可以从一个得到这个值
time.Time
其价值Time.UnixNano()
方法,然后除以1000000
(摆脱纳秒毫秒),例如:
fmt.Println(time.Now().UnixNano() / 1000000) // Output: 1455526958178
Note that in order to have time values as strings in the JSON output, you have to add these time values as string
s in the []ChartElement
. 请注意,为了使时间值在JSON输出中作为字符串,您必须在
[]ChartElement
中将这些时间值作为string
s添加。 To convert this millisecond value to string
, you can use strconv.FormatInt()
, eg 要将毫秒值转换为
string
,可以使用strconv.FormatInt()
,例如
t := time.Now().UnixNano() / 1000000
timestr := strconv.FormatInt(t, 10) // timestr is of type string
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.