匹配特定文件路径正则表达式

Question

so far I have this regex $fileregex = /([az]:\\\\\\\\([^\\\\\\\\^\\\\.])*)|(\\/[^\\/.])/i; but I am very confused on what to do next.

I want to match strings in this format

c:\\something\\else\\something
c:\\something\\else\\something.whatever
/etc/whatever/something/here
/etc/here.txt
/
c:\\

But I don't want to match, for example

c:\oneslash\text.txt
\etc\hi

I am really stuck on my regex especially on repeating the optional path, as one could just request the root.Can anyone help me out with the regex?

Answer 1

This one should work:

preg_match_all('%[A-Za-z]:\\\\\\\\(.*?\\\\\\\\)*.*|/(.*?/)*.*%m', $input, $regs, PREG_PATTERN_ORDER);
for ($i = 0; $i < count($regs[0]); $i++) {
    # Matched text = $regs[0][$i];
}

Result:

Description of the Regex:

                Match either the regular expression below (attempting the next alternative only if this one fails)
    [A-Za-z]        Match a single character present in the list below
                      A character in the range between “A” and “Z”
                      A character in the range between “a” and “z”
    :               Match the character “:” literally
    \\\\              Match the character “\” literally
    \\\\              Match the character “\” literally
    (               Match the regular expression below and capture its match into backreference number 1
      .               Match any single character that is not a line break character
         *?              Between zero and unlimited times, as few times as possible, expanding as needed (lazy)
      \\\\              Match the character “\” literally
      \\\\              Match the character “\” literally
    )*              Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
    .               Match any single character that is not a line break character
      *               Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
|               Or match regular expression number 2 below (the entire match attempt fails if this one fails to match)
   /               Match the character “/” literally
   (               Match the regular expression below and capture its match into backreference number 2
      .               Match any single character that is not a line break character
         *?              Between zero and unlimited times, as few times as possible, expanding as needed (lazy)
      /               Match the character “/” literally
   )*              Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   .               Match any single character that is not a line break character
      *               Between zero and unlimited times, as many times as possible, giving back as needed (greedy)

Answer 2

Have you try this:

/^([a-zA-Z]\:|\\\\[^\/\\:*?"<>|]+\\[^\/\\:*?"<>|]+)(\\[^\/\\:*?"<>|]+)+(\.[^\/\\:*?"<>|]+)$/

This regular expression will match any valid file path. It checks local drives and network path. The file extension is required.

Further references : The regular expression library