带有gulp的ArangoDB foxx-manager不知道命令--server.database

Question

I want to run setup.js script every time i change it. I wrote following gulp script:

gulp.task('db_server_setup', function(){
    gulp.src(paths.db_server_setup)
        .pipe(gulp.dest(paths.db_dist))
        .pipe(callback(() => {
            process.execFile('C:/Program Files/ArangoDB 2.8/bin/foxx-manager.exe', ['--server.database "my_db_name" run "/db" setup'], {stdio: 'inherit'}, exec_output);
        }));
});

But it results in:

{ [Error: Command failed: C:/Program Files/ArangoDB 2.8/bin/foxx-manager.exe --server.database "my_db_name" run "/db" setup C:/Program Files/ArangoDB 2.8/bin/foxx-manager.exe: unrecognized option '--server.database "my_db_name" run "/db" setup' Did you mean one of these? --help --quiet 2016-02-16T13:42:17Z [1564] FATAL illegal option ] killed: false, code: 1, signal: null, cmd: 'C:/Program Files/ArangoDB 2.8/bin/foxx-manager.exe --server.database "my_db_name" run "/db" setup' } C:/Program Files/ArangoDB 2.8/bin/foxx-manager.exe: unrecognized option '--server.database "my_db_name" run "/db" setup'

Did you mean one of these? --help --quiet

2016-02-16T13:42:17Z [1564] FATAL illegal option

When I exec "C:/Program Files/ArangoDB 2.8/bin/foxx-manager.exe" --server.database "organize_me" run "/db" setup it runs succesfully

{"code": 200}

How can i achieve to rerun setup script with gulp everytime I change it? Thanks

Answer 1

This looks more like a Node problem than an ArangoDB problem.

child_process.execFile takes the name of an executable as well as an arguments array. Your arguments array currently looks like this:

['--server.database "my_db_name" run "/db" setup']

As far as I can tell that is the equivalent of passing the following argument on the command line:

"--server.database \"my_db_name\" run \"/db\" setup"

So what you actually want is probably this:

['--server.database', 'my_db_name', 'run', '/db', 'setup']