将两个或多个JSON对象数组合并为一个数组，以保持唯一性

Question

I have two arrays of JSON objects, I am trying to merge them into one array, by date, without creating any duplicates. jQuery's extend() function does not seem to do the trick for me. I realize it's possible to use nested $.each statements, but the data in focus here can become very large, so I would rather avoid O(Log N * Log M)...

[  
   {  
      "date":"2016-03-16",
      "timesOff":[
         "18:00 - 20:00",
         "20:00 - 22:00"
      ],
      "appointments":[  
         {  
            "projectId":"adbc5010-ea7d-4993-b442-24cce609c3f8",
            "customerName":"Johnny",
            "timeSlot":"10:00 - 12:00",
            "startTime":""
         },
         {  
            "projectId":"60e0bed4-141b-46f0-91cd-f570fb1f886d",
            "customerName":"Jimmy",
            "timeSlot":"14:00 - 16:00",
            "startTime":""
         }
      ]
   },
   {  
      "date":"2016-03-02",
      "timesOff":[
         "10:00 - 12:00",
         "14:00 - 16:00"
      ],
      "appointments":[  
         {  
            "projectId":"041b6496-4905-42b3-8057-87dc2b8c482a",
            "customerName":"Billy",
            "timeSlot":"08:00 - 10:00",
            "startTime":""
         },
         {  
            "projectId":"f6e0743a-e714-4c92-be63-a14898ec1e4d",
            "customerName":"Bob",
            "timeSlot":"10:00 - 12:00",
            "startTime":""
         }
      ]
   }
]

[
   {  
      "date":"2016-03-16",
      "timesOff":[  
         "14:00 - 16:00",
         "18:00 - 20:00"
      ],
      "appointments":[  
         {  
            "projectId":"041b6496-4905-42b3-8057-87dc2b8c482a",
            "customerName":"Billy",
            "timeSlot":"08:00 - 10:00",
            "startTime":""
         },
         {  
            "projectId":"f6e0743a-e714-4c92-be63-a14898ec1e4d",
            "customerName":"Bob",
            "timeSlot":"10:00 - 12:00",
            "startTime":""
         }
      ]
   },
   {  
      "date":"2016-03-02",
      "timesOff":[  
         "18:00 - 20:00",
         "20:00 - 22:00"
      ],
      "appointments":[  
         {  
            "projectId":"041b6496-4905-42b3-8057-87dc2b8c482a",
            "customerName":"Billy",
            "timeSlot":"08:00 - 10:00",
            "startTime":""
         },
         {  
            "projectId":"f6e0743a-e714-4c92-be63-a14898ec1e4d",
            "customerName":"Bob",
            "timeSlot":"10:00 - 12:00",
            "startTime":""
         }
      ]
   }
]

These should be merged like so:

[  
   {  
      "date":"2016-03-16",
      "timesOff":[
         "14:00 - 16:00",
         "18:00 - 20:00",
         "20:00 - 22:00"
      ],
      "appointments":[  
         {  
            "projectId":"041b6496-4905-42b3-8057-87dc2b8c482a",
            "customerName":"Billy",
            "timeSlot":"08:00 - 10:00",
            "startTime":""
         },
         {  
            "projectId":"f6e0743a-e714-4c92-be63-a14898ec1e4d",
            "customerName":"Bob",
            "timeSlot":"10:00 - 12:00",
            "startTime":""
         },
         {  
            "projectId":"adbc5010-ea7d-4993-b442-24cce609c3f8",
            "customerName":"Johnny",
            "timeSlot":"10:00 - 12:00",
            "startTime":""
         },
         {  
            "projectId":"60e0bed4-141b-46f0-91cd-f570fb1f886d",
            "customerName":"Jimmy",
            "timeSlot":"14:00 - 16:00",
            "startTime":""
         }
      ]
   },
   {  
      "date":"2016-03-02",
      "timesOff":[
         "10:00 - 12:00",
         "14:00 - 16:00",
         "20:00 - 22:00"
      ],
      "appointments":[  
         {  
            "projectId":"041b6496-4905-42b3-8057-87dc2b8c482a",
            "customerName":"Billy",
            "timeSlot":"08:00 - 10:00",
            "startTime":""
         },
         {  
            "projectId":"f6e0743a-e714-4c92-be63-a14898ec1e4d",
            "customerName":"Bob",
            "timeSlot":"10:00 - 12:00",
            "startTime":""
         },
         {  
            "projectId":"041b6496-4905-42b3-8057-87dc2b8c482a",
            "customerName":"Billy",
            "timeSlot":"08:00 - 10:00",
            "startTime":""
         },
         {  
            "projectId":"f6e0743a-e714-4c92-be63-a14898ec1e4d",
            "customerName":"Bob",
            "timeSlot":"10:00 - 12:00",
            "startTime":""
         }
      ]
   }
]

My first thought of approach was to run $.each on both of the arrays separately at the same time, then assign values to temporary variables (ie x[value.date] = value) and then run $.extend against both of them. This works, however it returns an array like ["2016-03-02":Object, "2016-03-16":Object], which will not work for the purpose of the application. How can I merge these without the "Something":Object?

Thanks in advance.

Answer 1

I think you need two phpjs tools.

http://phpjs.org/functions/array_merge/ (merge arrays)

OR

http://phpjs.org/functions/array_merge_recursive (merge arrays with recursive mode, I think it's your requirement)

AND

http://phpjs.org/functions/array_unique (delete duplicated and empty elements in array)

Combine merge + unique and you'll obtain the expected results. Just copy and paste the function definition and then use them