简体   繁体   English

py2neo中的节点可以继承吗?

[英]Can Nodes in py2neo be inherited?

I am building an application in Flask using py2neo as a graph database. 我正在使用py2neo作为图形数据库在Flask中构建应用程序。 I have a node for a generic item, and a node for a specific implementation of that item. 我有一个用于通用项目的节点,以及一个用于该项目的特定实现的节点。 What I want is that if I search for all the generic nodes, that the specific implementation of those nodes also appear in the results. 我想要的是,如果我搜索所有通用节点,那么这些节点的特定实现也将出现在结果中。 I would usually just inherit the Node as an object, but according to this question , py2neo throws an exception. 我通常只继承Node作为对象,但是根据这个问题 ,py2neo抛出异常。 The answer given in that question is specific for Django, so it is not useful for me since I am using Flask. 该问题中给出的答案是特定于Django的,因此对我来说没有用,因为我正在使用Flask。

How would this be implemented? 如何实施?

I am able to implement this by using node.labels.add() function as described in this documentation and just add labels to that node. 我可以通过使用本文档中介绍的node.labels.add()函数来实现此目的,并且只需向该节点添加标签即可。 It achieves the same purpose. 它达到了相同的目的。 This can also be done in Cypher as described in this reference document by using the SET n:Label command. 也可以使用SET n:Label命令在Cypher中完成此参考文档中所述的操作。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM