嵌套用于循环以列出理解

Question

Given an OrderedDict d , I'd like to convert a nested for loop to a list comprehension. The OrderedDict d looks like this:

import collections
import numpy as np

d = collections.OrderedDict(
    [
        (
            60.0, 
            {
                Timestamp('2016-03-24 00:00:00'): np.nan, 
                Timestamp('2016-03-11 00:00:00'): 2.0173333333333336, 
                Timestamp('2016-02-19 00:00:00'): np.nan, 
                Timestamp('2016-02-26 00:00:00'): np.nan, 
                Timestamp('2016-03-04 00:00:00'): np.nan, 
                Timestamp('2016-03-18 00:00:00'): np.nan, 
                Timestamp('2016-04-01 00:00:00'): np.nan
            }
        ), (
            65.0, 
            {
                Timestamp('2016-03-24 00:00:00'): np.nan, 
                Timestamp('2016-03-11 00:00:00'): np.nan, 
                Timestamp('2016-02-19 00:00:00'): np.nan, 
                Timestamp('2016-02-26 00:00:00'): np.nan, 
                Timestamp('2016-03-04 00:00:00'): 1.8621538461538463, 
                Timestamp('2016-03-18 00:00:00'): np.nan, 
                Timestamp('2016-04-01 00:00:00'): np.nan
            }
        )
    ]
)

You'll notice there are unordered dicts as values. My goal is to order the "internal" dicts by timestamp, the return the values of the "internal" dict. Finally, I need to combine the key of the "internal" dicts with the values. Result should look like this:

[
    [60.0, nan, nan, nan 2.0173333333333336, nan, nan, nan],
    [65.0, nan, nan, 1.8621538461538463, nan, nan, nan, nan]
]

The following code prints this out nicely and I want to avoid appending to a list:

for k,v in d.iteritems():
    od = collections.OrderedDict(sorted(v.items()))
    for k_, v_ in od.iteritems():
        print k, k_, v_

I've also tried the following but it does not sort by key:

for row in [[k] + sorted(v.values()) for k, v in d.iteritems()]:
    print row

Therefore, looking to convert this to a list comprehension.

Answer 1

[[k] + [v_[1] for v_ in sorted(v.items())] for k,v in d.iteritems()]