如何在php中将数据插入到现有的html表中？
[英]How to insert data into an existing html table in php?
问题描述
I want to insert data which returns from the php code , into an existing html table (name = "userDetails"). 
我想将从php代码返回的 数据插入到现有的html表中 （名称=“ userDetails”）。
Number of rows in the html table would be different according to the results receiving from the mysql database. html表中的行数会根据从mysql数据库接收到的结果而有所不同。 How can I do that? 我怎样才能做到这一点？
Code is as follows, 代码如下，
<?php
$connection = mysqli_connect('localhost', 'root', '', 'users');
$sql = "SELECT id, firstname,email FROM usertable";
$result = mysqli_query($connection, $sql);
$userDetailsArray = array();
if(mysqli_num_rows($result) > 0){
$index = 0;
while ($row = mysqli_fetch_assoc($result)) {
$userDataArray[$index] = $row;
$row = $userDataArray[$index];
$userID = $row['id'];
$firstName = $row['firstname'];
$email = $row['email'];
$index++;
}
}
?>
<html>
<head></head>
<body>
<table name = "userDetails">
<tr>
<th>User ID</th>
<th>First Name</th>
<th>email</th>
</tr>
</table>
</body>
<html/>
3 个解决方案
解决方案1
1 已采纳 2016-02-18 08:22:45
Looks like you're looking for something like this: 看起来您正在寻找这样的东西：
<html>
<head></head>
<body>
<table name = "userDetails">
<tr>
<th>User ID</th>
<th>First Name</th>
<th>email</th>
</tr>
<?php
$connection = mysqli_connect('localhost', 'root', '', 'users');
$sql = "SELECT id, firstname,email FROM usertable";
$result = mysqli_query($connection, $sql);
if(mysqli_num_rows($result) > 0){
while ($row = mysqli_fetch_assoc($result)) {
echo '<tr>';
echo '<td>'. $row['id'] .'</td>';
echo '<td>'. $row['firstname'] .'</td>';
echo '<td>'. $row['email'] .'</td>';
echo '</tr>';
}
}
?>
</table>
</body>
<html/>
You can simply generate HTML in your while loop. 您可以在while循环中简单地生成HTML。 Not the best possible strategy, but it certainly gives results. 这不是最好的策略，但肯定可以带来结果。
解决方案2
0 2016-02-18 08:22:25
using same page means it will work. 使用同一页面意味着它会工作。 try this 尝试这个
while ($row = mysqli_fetch_assoc($result))
{
$userDataArray[$index] = $row;
$row = $userDataArray[$index];
echo "<tr><td>".$row['id']."</td>";
echo "<td>".$row['firstname']."</td>"";
echo "<td>".$row['email']."</td></tr>"";
$index++;
}
解决方案3
0 2016-02-18 08:52:06
what are the requirements of these lines in your code actualy? 这些代码实际上对您的代码有什么要求？ $userDetailsArray = array(); $ userDetailsArray = array（）; $userDataArray[$index] = $row; $ userDataArray [$ index] = $ row; $row = $userDataArray[$index]; $ row = $ userDataArray [$ index]; ??and even what is the requirement of $index variable? 甚至$ index变量有什么要求？
i am adding changes to you program here. 我在这里向您的程序添加更改。
<?php
$connection = mysqli_connect('localhost', 'root', '', 'users');
?>
<html>
<head></head>
<body>
<table name = "userDetails">
<tr>
<th>User ID</th>
<th>First Name</th>
<th>email</th>
</tr>
<?php
$sql = "SELECT id, firstname,email FROM usertable";
$result = mysqli_query($connection, $sql);
if(mysqli_num_rows($result) > 0){
while ($row = mysqli_fetch_assoc($result)) {
?>
<tr>
<td>$row['id'];</td>
<td>$row['firstname'];</td>
<td>$row['email'];</td>
</tr>
<?php
}
}
else
{
?>
<tr>
<td colspan=3>Data is not available</td>
</tr>
<?php
}
?>
</table>
</body>
<html/>
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