[英]SyntaxError: invalid syntax after Cast a string to int
I have written a piece of code in python and when I let it run I get the following message: 我已经用python写了一段代码,当我让它运行时,我收到以下消息:
File "port.py", line 229
port = (int) a
^
SyntaxError: invalid syntax
since the code is a little bit too long, I give only the important part in the following section: 由于代码有点太长,因此在以下部分中仅给出重要部分:
try:
opts, args = getopt.getopt(sys.argv[1:], 'hle:t:p:cu:',
['help','listen','execute', 'target',
'port', 'command', 'upload'])
except getopt.GetoptError as err:
print(str(err))
usage()
for o,a in opts:
if o in ('-h', '--help'):
usage()
elif o in ('-l','--listen'):
listen = True
elif o in ('-e', '--execute'):
execute = a
elif o in ('-c','--commandshell'):
command = True
elif o in ('-u','--upload'):
upload_destination = a
elif o in ('-t','--target'):
target = a
elif o in ('-p','--port'):
port = (int) a
else:
assert False,'Unhandled Option'
So, the a should be the port number which has string as type. 因此, a应该是具有字符串作为类型的端口号。 So, I thought that I should cast it. 所以,我认为我应该抛弃它。
The version of python is 2.7.3. python的版本是2.7.3。
I could not figure out why the error message appears. 我不知道为什么会出现错误消息。 I hope somebody can help. 希望有人能帮忙。
Best regards, 最好的祝福,
要从字符串a
创建一个新的int
对象,请使用
port = int(a)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.