[英]how to fetch word from url in php?
url string 网址字串
http://localhost/magento_prac/index.php/electronics/computers.html
http://localhost/magento_prac/index.php/electronics/cell-phones.html
I want to fetch 'computers' from url. 我想从网址获取“计算机”。 ex 'computers', 'cell-phones' 前“计算机”,“手机”
Try something like 尝试类似
$category = preg_replace('/^.*\/(.*)\.html$/', '$1', $url);
The regular expression matches everything ( .*
) from the start ( ^
) of the string up until the last / ( \\/
). 正则表达式匹配从字符串开头( ^
)到最后一个/( \\/
)的所有内容( .*
)。 Then, it matches everything ( .*
) again except for the .html
at the end and expects the string to end after that ( $
). 然后,它再次匹配所有内容( .*
),但结尾处的.html
除外,并期望字符串在该字符串( $
)之后结束。
The brackets around the second .*
allow you to reference that part of the match in the substitution as $1
. 第二个.*
周围的方括号允许您将替换中匹配的那部分称为$1
。
You can convert URL into attay and fetch last element with array_pop(): 您可以将URL转换为attay并使用array_pop()获取最后一个元素:
$urlArray = explode('/', $url);
$word = substr(array_pop($urlArray),0,-5);
try this code: 试试这个代码:
//get the url
$url = parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH);
//seperate the segments using explode()
$segments = explode('/', $url);
//and get the last segment
$last = explode('.', end($segments));
//use the last segment
echo $last[0];
For convenience, here's another option: 为了方便起见,这是另一个选择:
$url = 'http://localhost/magento_prac/index.php/electronics/computers.html';
$category = pathinfo($url)['filename']; // "computers"
Above example assumes the application is running at least on PHP 5.4 to use array de-referencing. 上面的示例假定应用程序至少在PHP 5.4上运行以使用数组取消引用。
pathinfo
- Returns information about a file path.pathinfo
返回有关文件路径的信息。
'dirname' => string 'http://localhost/magento_prac/index.php/electronics'
'basename' => string 'computers.html'
'extension' => string 'html'
'filename' => string 'computers'
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