[英]upload image through a form by Ajax
I have a data in a form which is opening in a popup. 我有一个在弹出窗口中打开的表格中的数据。 which is editable by the users.
用户可以对其进行编辑。 All the data has been edited, except the image.
除图像外,所有数据均已编辑。 it is giving me an error of "undefined index file in c/xamp/htdocs/website/file.php on line 35"
它给我一个错误“第35行的c / xamp / htdocs / website / file.php中的未定义索引文件”
my ajax call is :
function updat(id){
$.ajax({
url:'file.php?upd='+id,
success:function(response){
var img = $("#file").val();
var marlas = $("#marlas").val();
var bath= $("#bath").val();
var bed = $("#bed").val();
var house_no = $("#house_no").val();
var address = $("#address").val();
var price = $("#price").val();
var ids = $("#ids").val();
var dataString = 'files='+ img + '&marlas1='+ marlas + '&bath1='+ bath + '&bed1=' + bed + '&house_no1=' + house_no + '&address1=' + address + '&price1=' + price +'&ids1=' + ids;
$.ajax({
type: "POST",
url: "file.php",
data: dataString,
success: function(result){
document.getElementById("update");
alert(result);
window.location.reload();
}
});
}
});
}
my file code is :
if(isset($_POST['ids1'])){
$ids= $_POST['ids1'];
$file= $_POST['files'];
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["files"]["name"]);
print_r($target_file); exit();
$file=$_FILES["files"]["name"];
$fsize=$_FILES["files"]["size"];
$ftype=$_FILES["files"]["type"];
$tmp_name=$_FILES["files"]["tmp_name"];
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
}
move_uploaded_file($_FILES["files"]["tmp_name"], $target_file);
$marlas= $_POST['marlas1'];
$bath= $_POST['bath1'];
$bed= $_POST['bed1'];
$house_no= $_POST['house_no1'];
$address= $_POST['address1'];
$price= $_POST['price1'];
$q= mysql_query("update property set img='$file', marlas='$marlas', bath='$bath', bed='$bed', house_no= '$house_no', address='$address', price='$price' where id='$ids'");
if(!$q){echo 'error'.mysql_error(); }
else echo "property updated";
}
You can create a Function to handle file uploads and reuse it. 您可以创建一个功能来处理文件上载并重新使用它。 Below is the code illustrating the same.
以下是说明该代码的代码。 Also the function has a callback that is called on success of the upload.
该函数还具有一个上载成功时调用的回调。
var Url = "YourApplicationUrlToPostTheFile"; //file.php
AjaxFileUpload($('input[type="file"]')[0], Url, function (response) {
alert('File Uploaded, And the response is ' + response);
// do something after the image is uploaded successfully;
});
And the Ajax function to upload the file . 和Ajax函数一起上传文件。
function AjaxFileUpload($element, Url, callback) {
var formdata = new FormData();
var totalFiles = $element.files.length;
if (totalFiles > 0) {
for (var i = 0; i < totalFiles; i++) {
var file = $element.files[i];
formdata.append("FileUpload", file);
}
$.ajax({
type: "POST",
url: Url,
data: formdata,
contentType: false,
processData: false,
success: function (result) {
callback(result);
},
error: function (error) {
console.log("File Upload Failure");
}
});
}
}
Let me know if you have any issues. 如果您有任何问题,请告诉我。
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